Monday, May 26, 2014

Physics 9702 Notes | Worked Solutions for Past Papers

  • Physics 9702 (A-Level) Notes & Worked Solutions for Past Exam Papers


This page contains links to notes for the different chapters of the 9702 Physics syllabus (AS and A-Level) as well as worked solutions (explanations + details) for past exam papers. You may clear any of your doubts at the respective pages.


IF YOU ARE USING THE ANSWERS PROVIDED BY THIS SITE ON OTHER WEBSITES, PLEASE PROVIDE A LINK TO THE SPECIFIC PAGES OF THIS SITE


More notes and worked solutions will be added soon. Be sure to check again frequently.


Some solutions are temporarily displayed here until solutions for the complete paper is available later.


Physics 9702 (A-Level) Guide


Recommended books | Syllabus 2016 Changes |
Exam Structure | Exam Tips | Skills to be tested? | Details of Topics |

A-Levels to MCAT Guide




Physics 9702 (A-Level) Notes


Graphs:
Physics Graphs Basics 1 – Coordinates of Points | 2 - Nature of Gradients |


Units - Base (Fundamental) and Derived | Homogeneity
Uncertainty - no. of significant figures (Check Solution 1022)

Adding vectors graphically (Check Solution 703)


Types of Forces - Gravitational, Electric, Frictional, Viscous drag and Upthrust
Weightlessness (Check Solution 989)

Springs in series and in parallel (Check solution 925)



Circular motion in a vertical plane
Derive escape velocity (Check Solution 338)

Kepler's 3rd law of Gravitation (Check Solution 948)


Concept of 'Internal Energy' + examples (Check Solution 588)


Diffraction of water water in ripple tank (Check Solution 858)
How to draw waves with a phase difference? (Check Solution 318)

Ideal diode (Check Solution 675)

Quantisation of Charge (Check Solution 727)

Specific charge (Check Solution 971)


Binary numbers (Check Solution 555)
ADC and DAC: Reproduction of an input signal (Check Solution 667)





Physics 9702 Summary notes (by Zubair Junjunia, Emir Demirkhan & Saif Asmi)
AS:
1. Physical Quantities and Units | 2. Measurement Techniques | 3. Kinematics | 4. Dynamics | 5. Forces |



Complete A-Level Physics 9702 notes for syllabus 2015 (Credit: Neha of India)


Physics 9702 (A-Level) Worked Solutions for Past Papers


Year 2014
Past Exam Paper November 2014 Paper 11 & 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 43 Worked Solutions | A-Level Physics 9702

Past Exam Paper June 2014 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 41 & 43 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 42 Worked Solutions | A-Level Physics 9702


Year 2013
Past Exam Paper November 2013 Paper 11 & 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 21 & 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 43 Worked Solutions | A-Level Physics 9702

Past Exam Paper June 2013 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 42 Worked Solutions | A-Level Physics 9702


Year 2012
Past Exam Paper November 2012 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2012 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2012 Paper 41 & 42 Worked Solutions | A-Level Physics 9702


Past Exam Paper June 2012 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2012 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2012 Paper 42 Worked Solutions | A-Level Physics 9702


Year 2011
Past Exam Paper November 2011 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2011 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2011 Paper 41 & 42 Worked Solutions | A-Level Physics 9702


Past Exam Paper June 2011 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2011 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2011 Paper 42 & 43 Worked Solutions | A-Level Physics 9702


Year 2010

Past Exam Paper November 2010 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2010 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2010 Paper 41 & 42 Worked Solutions | A-Level Physics 9702

Past Exam Paper June 2010 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 42 & 43 Worked Solutions | A-Level Physics 9702


Year 2009
Past Exam Paper November 2009 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 42 Worked Solutions | A-Level Physics 9702


Past Exam Paper June 2009 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 22 Worked Solutions | A-Level Physics 9702


Year 2008
Past Exam Paper November 2008 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2008 Paper 2 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2008 Paper 4 Worked Solutions | A-Level Physics 9702

Past Exam Paper June 2008 Paper 1 Worked Solutions | A-Level Physics 9702



Year 2007

Past Exam Paper November 2007 Paper 2 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2007 Paper 4 Worked Solutions | A-Level Physics 9702



Past Exam Paper June 2007 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2007 Paper 2 Worked Solutions | A-Level Physics 9702


Year 2005

Past Exam Paper November 2005 Paper 2 Worked Solutions | A-Level Physics 9702


Year 2004

Past Exam Paper June 2004 Paper 2 Worked Solutions | A-Level Physics 9702






Question:
can you tell me if i am reading a volume on a cylinder.....
what error may occur?
and what are the possible improvements?


Explanation:
The measurements to be made are that of the diameter and the length of the cylinder using a vernier caliper (for both).

So, it is obvious that you should know how to handle and record measurements from a vernier caliper. Also, handle the caliper with care and take the necessary precautions (do not squeeze the object, insert object perpendicularly (not diagonally), …)

A possible error that may arise is zero error. This can be prevented by first bringing the jaws of the caliper together, before taking any measurements, and verify whether the zero mark of the vernier scale coincide with the zero mark of the main scale. If it does then you may record measurements directly. If not, then apply the appropriate correction before recording the measurements.

Measurements of the diameter should be taken at different positions (at least 3) along the cylinder and an averaged value can be calculated. The same is done for the length (you can take 2 or 3 measurements).









Question:
The crane shown in the figure lifts its 500N load to the top of the building from A to B. Distances are as shown on the diagram. Calculate how much work is done by the crane.

The dotted line shows the track of the load as it is lifted by the crane.
[Ans: 20kJ]
Reference: Cambridge International AS and A Level Physics Coursebook – 2nd edition – by Sang, D., Jones, G., Woodside, R. and Chadha, G.




Solution:
Work done = Force x Displacement in direction of the force
The load is first lifted vertically from A to a height of 40m (the height of the building). It is moved (horizontally from that position to point B)

To lift load vertically (an upward force is required) from A to a height of 40m,
Work done = 500 x 40 = 20 000J

Now, to keep the load at this position, an upward force is still needed. But now, the load is moved horizontally. So, work done for this movement is ZERO since force is vertical while the displacement is horizontal [there is no component of displacement in the direction of the force]

So, work done by the crane = 20 000kJ = 20kJ






Question:
Reference: Cambridge International AS and A Level Physics Coursebook with CD-ROM by David Sang, Graham Jones, Gurinder Chadha, Richard Woodside - Cambridge University Press, 2014 Pg 326 Chapter 20: Communication systems
 

Figure 20.21 shows the variation with time of a signal voltage, V, over a 5-hour period.

a State the name of the type of signal shown in the diagram.
b The signal is turned into a digital signal with 4-bit binary numbers. The value is (0000) when V is 3V and each subsequent binary unit represents an extra 0.2V. Copy and complete the table to give the value of V as a decimal number and as a binary number for times 0, 2 and 4 hours.


Solution:
(a)
Analogue signal

(b)
A 4-bit binary number can only consist of ‘0’s and ‘1’s. [these are called bits] The 4-bit binary numbers have the bits 0 0 0 0 (in this order) corresponding to 23 22 21 20 respectively [which corresponds to 8 4 2 1 respectively]. {The values given in square brackets next are the numbers of binary units}That is, for the right-most bit, a ‘0’ corresponds to 0 x (20) [= 0 binary unit] while a ‘1’ corresponds to 1 x (20) [= 1 binary unit]. For the left-most bit, a ‘0’ would therefore correspond to 0 x (23) [= 0 binary unit] while a ‘1’ would correspond to 1 x (23) [= 8 binary units]

The total number of binary units represented by the 4-bit binary number is equal to the sum of binary units of each bit.

Examples:
4-bit binary number: 0000
Number of binary bits: 0 + 0 + 0 + 0 = 0

4-bit binary number: 0001
Number of binary bits: 0 + 0 + 0 + 1 = 1

4-bit binary number: 0011
Number of binary bits: 0 + 0 + 2 + 1 = 3

4-bit binary number: 1011
Number of binary bits: 8 + 0 + 2 + 1 = 11

Now, it is said in the question that the value is (0000) when V is 3V and that each binary unit represents an extra 0.2V. 

So, for example, consider V = 3.4V [this value is given in decimal]. We need a number of binary units that would represent the extra here (which is 3.4 – 3.0 = 0.4). Since 0.2V is represented by 1 binary unit, the number of binary units representing 0.4V is 0.4 / 0.2 = 2 binary units. 

Now, in the 4-bit binary number, 2 binary units is represented by 0010. So, the same process is done to complete the table.

The decimal values can be read directly from the graph. The binary number is obtained as explained above.
From the graph, 5 small squares represent 1V. So, 1 small square = 0.2V.

At time = 0, V = 5.2V. The extra is 5.2 – 3.0 = 2.2V. This is represented by 2.2 / 0.2 = 11 binary units. In the 4-bit binary number, 11 is represented by 1011 {that is, 1(8) + 0(4) + 1(2) + 1(1) = 11}

At time = 2, V = 4.0V. The extra is 4.0 – 3.0 = 1.0V. This is represented by 1.0 / 0.2 = 5 binary units. In the 4-bit binary number, 5 is represented by 0101 {that is, 0(8) + 1(4) + 0(2) + 1(1) = 5}

At time = 4, V = 3.8V (it is a little less than 3.8V but we cannot read to value to that accuracy. Data is lost at such points). The extra is 3.8 – 3.0 = 0.8V. This is represented by 0.8 / 0.2 = 4 binary units. In the 4-bit binary number, 4 is represented by 0100 {that is, 0(8) + 1(4) + 0(2) + 0(1) = 4}

Time / hours    V / V (decimal)           V / V (binary)
0                      5.2V                            1011
2                      4.0V                            0101
4                      3.8V                            0100










Question:
Proper definition for a projectile?

Explanation:
An object upon which the only force that acts on it is gravity (that is, other forces such as air resistance is negligible) is called a projectile.
In 1-dimenion motion, an example of a projectile is an object thrown vertically upward (neglecting air resistance). This object would have a constant downward acceleration. The path of this object is along a straight line.
In 2-dimensions, a projectile can be an object thrown at an angle to the horizontal with a constant velocity. This object would have a constant horizontal component of velocity, while its vertical component would be subject to a constant downward acceleration (due to gravity). Again, air resistance is negligible. The path of this object is a trajectory.

207 comments:

  1. Replies
    1. June 2014 P12 & all the June 2014 papers' solutions will be added a little later (but of course before the November exams). But if you are having specific problems, you may asked about it here until the worked solutions are provided.

      Be sure to check later.
      In the meantime, more worked solutions of the earlier papers will be provided.

      Delete
  2. 9702_w09_qp_12 question 8 and 30.

    thank you :)

    ReplyDelete
    Replies
    1. 8 – Ans: A. For elastic collision, velocity of approach (before collision) = velocity of separation (after collision). velocity of approach = u + u = 2u. Only answer A gives velocity of separation = 2u.

      30 – Ans: C. Rate of energy transfer = Power. P = VI = I2R. Answer A gives P = 4Js-1. B gives 32Js-1. C gives 16Js-1 and D gives 256Js-1. So, ans = C.

      (the superscripts do not seem to work here but I think you can understand)

      Delete
  3. Aoa this site is very helpful. It's a blessing fr all students. May God bless yu. Lots of prayers.
    btw I hav a couple of questions if you'd help out i'll be grateful.
    9702_w07_qp_11 question 29 and 31

    9702_w05_qp_11 Q33

    9702_s05_qp_11 Q32

    9702_s11_qp_22 Q5

    ReplyDelete
    Replies
    1. Note: y^2: means y squared

      9702_w07_qp_1 question 29 and 31
      29 – Ans: D. P = VI = V^2/R. Px = Py. So, (12x12) / Rx = (6x6) / Ry. Rx / Ry = 144 / 36 = 4.

      31 – Ans: A. R = ρL/A. A = π(d/2)^2. So, R∝ L / (d/2)^2. Rq ∝ L / (d/2)^2 = 4L / d^2. Rp ∝ 2L / (2d/2)^2 = 2L / d^2. So, Rp / Rq = 2 / 4 = 0.5.
      For these type of questions, you need to write them down. Do not do it in your mind.


      9702_w05_qp_1 Q33
      33 – Ans: D. Strain = e/ L where e is the extension and L is the original length. An increase in the strain (extension) means increasing the length and this also causes the cross-sectional area to decrease. Now, R = ρL/A, so R increases


      9702_s05_qp_11 Q32
      32 – Ans: C. charge, Q = It so I = Q/t = 10. Now, the total charge Q = ne where n is the number of electrons and e is the charge of an electron = 1.6x10^-19C. So, ne / t = 10 and n /t is the number of electrons passing a given cross-section = 10 / (1.6x10^-19) = 6.3x10^19.
      [No need to use area here.]


      9702_s11_qp_22 Q5
      This is June 2011, which is already posted. Look at the links above.

      Hope it is clear to you

      Delete
  4. Nov 09 Paper 41 8(c)(ii)

    You need BE per nucleon. Tritium contains 3 nucleons and deuterium contains 2 nucleons. Values given in table are for BE 'per nucleon'.

    So LHS of equation = 2(1.12) + 3x
    where x is BE per nucleon for tritium.

    Similarly, RHS of equation = 4(7.07) – 17.7
    since helium contains 4 nucleons.

    Solving gives x = 2.78MeV

    ReplyDelete
  5. hi
    can i have work exam paper for year 2007 to 2010
    ?

    ReplyDelete
  6. the 2010 and earlier papers will be published next.

    check again later

    ReplyDelete
    Replies
    1. I`ll publish one every 3 days, i think (at the time of writing)
      This may change though

      Delete
  7. can u plz publish them
    i really need help

    ReplyDelete
    Replies
    1. if you are having SPECIFIC questions on the earlier papers, I will try to help as soon as possible. But plz, do not ask for all of them

      Delete
  8. hi can you plz upload the ms of november 2005 question paper 2 as quick as possible i badly need it !!!

    ReplyDelete
    Replies
    1. this will come a bit later. Check the others in the meantime.
      By the way, I do not upload MS. This is the worked solutions.

      Delete
    2. can u plz just help me out wiz the number 4, 5 and 8(b)

      Delete
    3. OK. I`ll try to look into the paper. At latest, you may obtain the solutions tomorrow

      Delete
  9. 9702_w08_qp_1 question 24.

    Thanks in advance :)

    ReplyDelete
    Replies
    1. 24 – Ans: D.
      Amplitude is the maximum displacement. Amplitude of Y is half that of X (as can be clearly seen in diagram), so amplitude of Y = 4cm. Frequency, f = 1 / T where T is period. For X, period = 1 / 100 = 0.01s. As seen from diagram, period of Y is one third that of X (3 oscillations occurs for the same amount of time), so period of Y = 0.01 /3. Frequency of Y = 1 / [0.01/3] = 300Hz. (or you could directly obtain the frequency to be 3 times that of X if you understand the concept of frequency well)

      Delete
  10. Question (November 2000 paper 1 question number 27):

    An early experimenter, working in other than Si units, obtained the following ten values for the magnitudes of the changes on small oil drops:
    9.82, 19.64, 39.28, 39.28, 34.37, 19.64, 19.64, 29.46, 19.64, 39.28.

    What value do these results suggest for the magnitude of the charge of the electron as measured in these units?
    A 2.45
    B 4.91
    C 9.82
    D 19.64



    Explanation:
    We are looking for the charge of an electron. The oil drop may contain 1 electron, or 2 or 3 or 4, (an integer) ... but not 1.5, 2.5, ... (we obviously cannot have half an electron). The charge of the oil drop would be that integer times the charge of an electron. From this info, we can eliminate all the values except the smallest one since the other need to be product of an integer with the charge of an electron. [D is eliminated]

    Now we look at the smallest value, which is 9.82. If we ASSUME that it IS the charge of an electron, then all others should be integral multiples of it. (That is, taking any of the values divided by the smallest one would give an integer. e.g: 19.64/9.82 = 2 , ...). If we try, all of them would give integers except 34.37 which gives 3.5 (not an integer). [C is eliminated]

    So, 9.82 cannot be the charge of an electron. We now take 4.91. This is half 9.82, so every value which were integral multiple of 9.82 will also be an integral multiple of 4.91. In this case, even 34.37 gives an integral (=7) when divided by 4.91. So, every value gives an integer with 4.91, making it the correct answer.

    But why is ans A incorrect? It is half 4.91, so it will also give integer with all the values?? But then, if we take another ans which = 2.45/2, it will also give integers! So, what we need is what is called Greatest Common Factor or Highest Common Factor

    ReplyDelete
  11. nov 2010
    paper42
    section B
    exercise 9,10,11,12

    ReplyDelete
    Replies
    1. I intended to provide this paper today but there was a request for Nov 2005 P2.
      So, the next worked solution is intended to be this one.

      Delete
    2. thanks.. hmm do u know on which site i can get the paper of june 2014?

      Delete
    3. just search it on Google. You should find it pretty quick. Insert the paper name + code (if you want), followed by the year, + include words like download, ...

      Delete
    4. btw on which paper you intend to publish next?

      Delete
    5. so when are u publishing the june 2014 solutions?

      Delete
    6. i need solution for these question nov 09
      paper 42
      no 9,10,11,12

      Delete
    7. i need solution for these question nov 09
      paper 42
      no 9,10,11,12

      Delete
    8. thanks :)))
      nov 12
      paper 12
      question: 6,10,16,24,25,29,33,34,35,39,40
      and nov 08
      paper 42
      no--5,7c(i) and(ii),9,11

      Delete
    9. For Nov 12 P12 Questions: 6, 10, 16, 33, 34, 39 already have explanations. You may check with the corresponding link above.

      I'll try to look into the others another time

      Delete
    10. can u plz explain me the question of june04 p22

      Delete
    11. Solutions for P2 June 2004 now available

      Delete
    12. nov 08
      paper 42
      no--5,7c(i) and(ii),9,11

      Delete
    13. hi can you plz tell me the difference btw advanced physics skill p33 and p34?
      becoz on my provisional timetable it was printed as p33
      and now on my final timetable it is printed as p34
      can you plz just clear my doubts.....:(

      Delete
    14. It's just the different variants for Paper 3. Just like some countries have Paper 11, others have paper 12. If I remember correctly, the paper for practicals is not the same for everyone. You just need to think of it as Paper 3.

      Delete
    15. ov 08
      paper 42
      no--5,7c(i) and(ii),9,11

      Delete
    16. Nov 2008 P4 Solutions now available

      Delete
    17. November 2007 Paper 4 worked solutions now available

      Delete
    18. nov 08 p22
      no.. 3,4(b),6,7,8
      nov 07 p22
      no... 5,6,7

      Delete
    19. November 2008 Paper 2 Worked Solutions available

      Delete
  12. Question: Test homogeneity
    1. P=rho*g*h......show if this is a homogeneous equation
    2.E=mc^2......show if this is a homogeneous equation

    1.
    Pressure, P = Force / Area = [mass][acceleration] / [area] = kg ms^-2 m-2 = kg m^-1 s^-2
    Now, density, rho = mass / volume = kg m^-3
    So, P = rho*g*h = kgm^-3 ms^-2 m = kg m^-1 s^-2
    So, homogeneous

    2.
    E = mc^2
    Energy, E = Force x distance = kg ms^-2 m = kg m^2 s^-2
    E = mc^2 = kg (ms^-1)^2 = kg m^2 s^-2
    So, homogeneous

    ReplyDelete
  13. 9702_w11_qp_13 Q13, 19, 29, 31, and 36 (Why cant it be A?)

    ReplyDelete
    Replies
    1. 13 – Ans: C. Let weight due to 1 ring = W. For rod to balance (equilibrium), Clockwise moment = Anticlockwise moment. Clockwise moment = 2[(13 – 8)xW] = 10W. Anticlockwise moment = (8 – 1)W + (8 – y)W = 10W where y is the position of hook where fourth ring must be hung. So, 7W + (8 – y)W = 10W. (8 – y)W = 3W. 8 – y = 3 giving y = 8 – 3 = 5.

      19 – Ans: A. Potential energy loss = E. Potential energy is also given as mgh where g is the g is the acceleration due to gravity and here h = x. So, E = mgx giving g = E / mx. Now, for the direction, consider the example of Earth. Gravitational field is TOWARDS the bigger mass (in the example, Earth) BUT a mass will have a higher potential energy when its HEIGHT (upwards distance from Earth) is higher. So, height is in opposite direction to the direction of the field. Since the mass loses potential energy when moved to the right, it is losing height and is going in direction of the field. So, ans A is correct.

      29 – Ans: C. Interference pattern is only along XY (although there can be 1 along PQ, but this was not an option). Note that waves are produced at P and Q. Phase difference between waves from P and Q is constant along line RS (since waves are coherent and RS is midway from P and Q), so there can be no interference pattern along RS. From this, ans A, B and D are eliminated.

      31 – Ans: C. Force = total EQ = E(+Q) + E(-Q) = 0. Electric field is from +ve to –ve. So, charge +Q will go downwards while charge –Q will go upwards (unlike charges attract) causing a resultant anti-clockwise torque.

      36 – Ans: D. Current is constant in a loop. Ans A and B actually give the same current. V = IR so I = V / R. The combined resistance of ans A and B is higher than that of ans C and D, so in A and B, current will actually be smaller than in C and D. Now, combined resistance of C and D are similar. Current starts from the +ve part of battery and at the left junction (point connecting the 2 resistors), it splits equally into 2 (its value is halved) and each half of the total current goes to a resistor. But before junction, current has not split yet, so it is greatest there. In ans C, current is already been split into half at the ammeter.

      Delete
  14. Question: November 2003 Paper 2 Question 2(b)
    2 situations where a body of constant mass may experience a change in its apparent weight:

    Situation 1:
    When the gravitational field strength changes {when the field is not constant – weight, W = mg so if g changes, W also changes. Also weight of a person on Moon is different from weight of same person on Earth}

    Situation 2:
    When (the body is immersed in a fluid) and then the fluid (surrounding the body) is changed {the resistive force (upthrust force) from the liquid would change. SO, there is now a resultant acceleration, a. Weight is then given by ma}

    Situation 3:
    When the body is accelerated in a lift {for same reason as in the fluid – there is a resultant acceleration. When the lift is accelerating downwards, weight is greater and if the lift is accelerating upwards, weight is less}

    ReplyDelete
    Replies
    1. Please note the following:

      Weight is the downward force exerted on a body by Earth's gravity while apparent weight is the normal reaction (upward) to weight. So, weight is constant while the apparent weight may vary. So, in situation 2, it's not 'weight is then given by ma', but the apparent weight.

      Also, situation 3 has been wrongly explained. Instead of weight, apparent weight should be used and when the lift is accelerating downwards, the apparent weight is less than the weight (since the resultant force on him is downwards,) and when accelerating upwards, the apparent weight (on him) is greater than the weight.

      Sorry for this mistake

      Delete
  15. can someone help me plz with the may/june 2011 paper 41 question numbers 10 and 11

    ReplyDelete
    Replies
    1. Solutions are temporarily available above

      Delete
  16. Here are solutions for some specific questions of Nov 11 P13:

    5 – Ans: B. Expanding the left hand side gives 3L + a^2 L/P. For equation to be homogeneous (and hence correct), the units should be the same on both sides of the equation and the units for 3L = units for a^2 L/P. L has unit m (since it is a distance), so all the different parts should have an overall unit of m. Considering the a^2 L/P: [m^2][m] / [P] = m. So, [P] = [m^3] / [m] = m^2. Now for QT^2 sinθ: sinθ has no units. So, [Q][s^2] = m giving [Q] = ms^-2.

    21 – Ans: B. For any specific material, the Young modulus is always constant. So, here E is constant for this particular type of steel since the SAME steel is used.

    25 – Ans: B. (I’m using capital L so that you may do not confuse between one (1) and small letter L (l)) For elastic compression, F = kΔL. Now, consider the Young modulus , E= stress / strain = (Force/Area) / (extension/original length). E α (original length) / (Area x extension). E α L / (L^2 x ΔL). E α 1 / (L x ΔL). So, ΔL α 1 / (E L) giving ΔL α 1 / L.

    30 – Ans: A. This is basic knowledge. Both pipes will give a stationary wave.

    37 – Ans: B. The potential difference, V across any loop is the same. V = IR, so when resistance is 2R, current should be I/2 so that pd = (I/2)(2R) = IR = V. Similarly, when resistance is 3R, current should be (I/3) so that pd = (I/3)(3R) = IR = V.

    ReplyDelete
  17. Solution for June 2011 Paper 13 Q19:

    19 – Ans: D. Total mass = mass of water + mass of alcohol = 1.5(1000) + 0.5(800) = 1900kg. Density = mass / volume = 1900 / 2 = 950kgm^-3.

    ReplyDelete
  18. Explanations for November 2011 Paper 51 Question 2 (c)(iv) & (d)(i), (ii) are temporarily available above

    ReplyDelete
  19. hi can u plz give some explanations for the 9702_s14_qp_12. Number 14,21,24 28,32 and 36.
    Plz upload the work solution as quick as u can !!!

    ReplyDelete
    Replies
    1. 9702 June 2014 Paper 12 Worked Solutions are now available

      Delete
  20. Explanations for November 2011 Paper 11 Question 16, 26, 28 and 29 are temporarily available above.

    ReplyDelete
  21. November 2003 Paper 1 Q35:

    35 – Ans: D. Electric field is from positive to negative. So, field lines should be towards the point charge –q. Field lines are straight lines here.

    ReplyDelete
  22. November 2002 Paper 1 Q35:
    35 – Ans: D.
    Let resistance of wire XY = W and resistance of variable resistor = R. From potential divider equation, potential difference across XY = V [W / (W+R)]. As R is increased, the pd across the wire decreases. Now, for galvanometer to show zero deflection, resistance of wire should be increased. Resistance of wire = ρL/A. So, length of wire, L (between X and N) should be increased. So, position of moveable contact should be nearer to Y.

    ReplyDelete
  23. June 2013 Paper 13 Q32 explanation is temporarily available above.

    ReplyDelete
  24. 9702/2007 paper1 November question 25 please explain and write the solutions. Thank you ! :)

    ReplyDelete
    Replies
    1. 25 – Ans: B. dsinθ = nλ. When n = 3 (third order), θ = 45 deg. So, dsin(45) = 3λ. So, d / λ = 3 / sin(45). For highest order if diffracted beam, angle should be less than 90 deg. So, consider angle θ = 90 deg. dsin(90) = nλ giving n = (d / λ) sin(90) = [3sin(90)] / sin (45) = 4.24. n should be an integer which is less than this. So, n = 4.

      Delete
  25. Do you mind explaining why 9702/11/ON/2009 question 9, 13, 14,15,17,21,23,26 and 40. Thank you!

    ReplyDelete
    Replies
    1. OK. But you may not obtain them today. I hope this is not a problem

      Delete
    2. November 2009 Paper 11 solutions are available

      Delete
  26. OK. But it will not be the next post since there's another request first

    ReplyDelete
    Replies
    1. june 2010 paper 42
      no.... 6,10,11
      and when are publishing the june 14 p42?

      Delete
  27. hi
    can you tell me if i am reading a volume on a cylinder.....
    what error may occur?
    and what are the possible improvements?

    ReplyDelete
    Replies
    1. some explanations have been added

      Delete
    2. hi i didnt get you
      meaning i cant understand what you have said

      Delete
    3. I will need to draw diagrams on pc to explain correctly. Sorry, but I don't I can make it before the exams

      Delete
    4. hi do you have simplified notes on the 3 main application topics?

      Delete
    5. No, but look at the application booklet and all the worked solutions for paper 4sec B available here. It should be enough

      Delete
    6. November 2009 Paper 22 worked solutions available at
      http://physics-ref.blogspot.com/2014/11/9702-november-2009-paper-22-worked.html

      Delete
  28. Its Paper 4 9702/O/N/2007 Qn 1. b) ii) Can you pls explain it in detail? tq :D

    ReplyDelete
    Replies
    1. details have been added at the page

      Delete
  29. 9702/21/ON/10 Q6(b) I know it's quite simple but can you explain to me? Part (i) n (ii) other than getting the answers by theory, is there a way I can work it out?

    ReplyDelete
    Replies
    1. look at qu2 at
      http://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-1.html

      Delete
  30. 9702/21/M/J/11 Q4 b(ii) and Q5 (b)

    ReplyDelete
    Replies
    1. questions correspond to qu3 and 4 at
      http://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-1.html

      Delete
  31. 9702/21/MJ/13 Q5(C) explanations. How to get the answer in marking scheme (5 maxima and 6 minima) ? Thanks

    ReplyDelete
    Replies
    1. it's explained as qu25 at
      http://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-4.html

      Delete
  32. 9702/02/M/J/05 question 6 (b)(i)

    ReplyDelete
    Replies
    1. check qu28 at
      http://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-4.html

      Delete
  33. 9702/22/ON/09 Q6(C)

    ReplyDelete
    Replies
    1. I'll post the worked solutions for this paper soon. Check again

      Delete
    2. worked solutions now available

      Delete
  34. hi, can you please draw me the graph on w05 paper 4 q6(c)(ii) ?

    ReplyDelete
    Replies
    1. Check qu 34 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-5.html

      I've explained the question there

      Delete
  35. 9702/22 MJ 2009
    5)(c) can you explain why? I don't understand the marking scheme.

    And 9702/ 21 MJ 2010
    4)(c) and 4)(d) I also don't understand the marking scheme either. Thank you :)

    ReplyDelete
    Replies
    1. Links for both papers are available above. If you still don't understand, specific your doubts at the respective pages

      Delete
  36. Can you post the working solutions for 9702 2010 p23 nov
    And explain question 3 ,5(b) and 6(b)(II) 1 thank you

    ReplyDelete
  37. 9702/02/MJ/08 Q6 step by step solution please...

    ReplyDelete
    Replies
    1. It's available as question 45 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-8.html

      Delete
  38. 9702/22/MJ/13 Q5(iii) You have provided answer. But I do not understand why horizontal line through PQ. Please explain. Thanks!

    ReplyDelete
    Replies
    1. I have included a link for the explanation at the page. Read it.

      Delete
    2. Got it.. TY! :)

      Delete
  39. Can you upload your working solutions for 2010 MJ P23 thank you :)

    ReplyDelete
  40. Replies
    1. check solution 64 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-12.html

      Delete
  41. do you have sample answer for p5?
    planning?

    ReplyDelete
    Replies
    1. currently none? but i once solved parts of 2 questions. they are available above

      Delete
  42. im having trouble to decide how many significant figure my answer should be. in the marking scheme it does not mention how many significant figures however it only shows one answer sometimes 2 significant and sometimes 3

    ReplyDelete
    Replies
    1. can you tell me to which question(s) you are referring? which year? I'll try to help based on them

      Delete
    2. for example in may june 2008 paper 2 question 3 why is the acceleration given to 2 significant figures but in c(i) it is given to 3 significant figures

      Delete
    3. Check question 79 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-15.html

      if you are still unsure, clear your doubts there

      Delete
  43. Hi, could you explain the may/ june 2013 paper 11 Q 18, 35

    ReplyDelete
    Replies
    1. Q18 is explained as solution 93 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-17.html

      the other one will be explained later

      Delete
    2. Q35 is explained as solution 100 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html

      Delete
  44. Oct/Nov 2002 Q15, 17, 28, 35 and 37.

    ReplyDelete
    Replies
    1. Q35 is explained as solution 99 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-18.html

      the others will be explained later

      Delete
    2. Q15 is explain as solution 103 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html

      Delete
    3. Q17 is explained as solution 109 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-21.html

      Delete
    4. Q28 is explained as solution 118 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-22.html

      Delete
    5. Q37 is explained as solution 122 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-23.html

      Delete
  45. can someone help me wiz zis question plz.
    Monochromatic light of wavelength 690 nm passes through a diffraction grating with 300 lines per mm, producing a series of maxima on a screen.What is the greatest number of maxima that can be observed

    ReplyDelete
    Replies
    1. It's from November 2012 Paper 12 Q30 and has already been explained. Use the corresponding link for the paper above.

      Delete
  46. Can someone help me with q7b) in M/J 07 and O/N 05 Q 6c)ii) and M/J 02 q6a) ?

    ReplyDelete
    Replies
    1. Nov 2005 Paper 2 worked solution is available at
      http://physics-ref.blogspot.com/2014/09/9702-november-2005-paper-2-worked.html

      (check links above)

      the others will be added soon

      Delete
  47. Can someone look at q5a)ii) 1. in MJ/2010/41? How to justify whether the expression is valid? Pls help me with the graph in MJ/2002 paper 4 q6a) and MJ/2007 paper 4 q7b)?

    ReplyDelete
    Replies
    1. For the MY/ 2007 Paper 4 Qu 7
      check qu 106 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-20.html

      I'll try to add the others as soon as possible

      Delete
  48. 9702/12/ON/11 Q 33, 37 and 38 please.

    ReplyDelete
    Replies
    1. Q33 has already been solved. Check ad
      http://physics-ref.blogspot.com/2014/08/9702-november-2011-paper-12-worked.html

      The others will be explained soon

      Delete
  49. 9702/11/MJ/13 Q 14, 18, 35. Thanks!

    ReplyDelete
    Replies
    1. Qu18 is available as solution 93 at Physics Doubts | Help Page 17
      (http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-17.html)

      and Qu35 is available as solution 100 at Physics Doubts | Help Page 19
      (http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html)

      Qu14 will be added soon

      Delete
    2. Q35 why do we take [1.5 / (1.5 + 0.75)] at the second loop and not [0.75 / (1.5 + 0.75)]?

      Delete
    3. Qu14 is available as solution 116 at Physics Doubts | Help Page 22
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-22.html

      Delete
    4. For Qu 35, some notes have been added. Read them carefully

      Delete
    5. Thanks for the extra notes ! ;)

      Delete
  50. 9702/12/ON/09 Q12 (Don't know how to get tension in top of belt), Q13, Q14, Q39 Don't understand the effect of gold nucleus on alpha particles)

    ReplyDelete
    Replies
    1. Qu 12 has been added at the November 2009 Paper 12 Worked Solutions link available above. Others will be added soon

      Delete
  51. Replies
    1. Details for this question has been added at the page

      Delete
    2. could u pls look into explaining me solns to 13/m/j/13 no. 14 &21
      i need them desperately

      Delete
    3. Qu 14 has been explained as solution 128 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-23.html

      Delete
  52. 9702/01/MJ/09 Q7, Q13 (After looking at answer I know how to get it, but don't understand the concept of the whole system how it works), Q18. TY!

    ReplyDelete
    Replies
    1. Q7 has been solved as solution 150 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html

      Others will be added soon

      Delete
  53. Need help on 9702/13/ON/13 Q15, 32, 33, 37. Thanks in advance!

    ReplyDelete
    Replies
    1. Q15 explained as solution 134 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-24.html

      Others will be added later

      Delete
    2. Qu32 explained as solution 141 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-25.html

      Delete
    3. Q33 explained as solution 153 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html

      Delete
  54. Can you please upload June 2013 paper13 working solutions? I have doubts for question 3, 5, 7,8, 10,11 ,19,30, 32, 35

    ReplyDelete
    Replies
    1. Q32 has been added as solution 141 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-25.html

      Others will be added soon

      Delete
    2. Q3 explained as solution 151 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html

      Q10 explained as solution 102 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html

      and Q32 explained as solution 142 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-25.html

      the other will be explained soon

      Delete
    3. Q30 has been added as solution 155 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html

      Delete
    4. Q11 added as solution 162 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-27.html

      Delete
    5. Q19 added as solution 171 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-28.html

      Delete
  55. could u pls explain me the answer of 01/m/j/09 q15

    ReplyDelete
    Replies
    1. It's explained as solution 64 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-12.html

      Delete
  56. June 2012 paper 13 question 8, 9, 10 ,13 thanks yea!

    ReplyDelete
  57. hi can you plz explain November 2008 p12 number 1 and 32

    ReplyDelete
  58. 11/M/J/10 q12 pls.......

    ReplyDelete
    Replies
    1. it's explained as 175 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html

      Delete
  59. november 2010 paper 12 q12

    ReplyDelete
    Replies
    1. the question is explained as solution 176 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html

      Delete
  60. Replies
    1. question is explained as solution 132 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-24.html

      Delete
  61. hi i need help for 9702/11/MJ/12 ques 12
    Thanks!

    ReplyDelete
    Replies
    1. the question is explained as solution 178 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html

      Delete
  62. need help on 9702/11/M/J/12 ques 12
    Thanks!

    ReplyDelete
  63. If i come out of the exam fully satisfied with my performance then i will not hesitate to fully dedicate my success to you. And once again thanks >>>

    ReplyDelete
  64. Here are my doubts
    1/O/N/02 Q.14
    01/M/J/03 Q.10
    03/M/J/03 Q.1(g)
    01/O/N/03 Q.5,6,11
    01/M/J/04 Q.9,21,23,25,26,27,28
    02/M/J/04 Q.2(b),Q.6(b) (Demonstration of graph and lines are required)
    01/O/N/04 Q.5,13,14
    01/M/J/05 Q.5,13,14,16,22,24,25
    02/M/J/05 Q.5(b)(i)(ii)
    01/O/N/05 Q.11,16

    ReplyDelete
    Replies
    1. Some questions are solved at
      http://physics-ref.blogspot.com/2014/12/physics-9702-doubts-help-page-32.html

      More will be added soon. If it's on a different page, I'll let you know through the replies to this comment

      Note: please post your future doubts at the doubts pages or the respective worked solution pages as asked above. Comments here will no longer be published. Hope you will co-operate. Thanks

      Delete
    2. More solutions have been added

      Delete
  65. just wanted to thankyou i got 90 in my as physics and it was largely for your help ^_^
    so thanks once again

    ReplyDelete
  66. Can you kindly solve 9702/01/M/J/03 Q20? Thank you!

    ReplyDelete
    Replies
    1. See solution 742 at
      http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-150.html


      NOTE:

      DO NOT POST ANY MORE COMMENTS HERE PLEASE.
      Use the other pages.

      COMMENTS HERE WILL NO LONGER BE CONSIDERED

      Delete
  67. This Blog is my Life Saviour. To a girl who always had difficulties with Physics, this has been of great help and I can't describe how grateful I am to have found this blog!

    ReplyDelete
  68. can u plzz help with qtn no.6 m/j 2008 p2

    ReplyDelete
    Replies
    1. See solution 45 at
      http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-8.html

      Delete
  69. this blog is amazing :)

    ReplyDelete
  70. Can you please tell me the answers for oct/nov 2009 9702 variant:41
    Q2 Q3(part 1) Q10 Q11.
    (Please do reply)

    ReplyDelete
    Replies
    1. For Q10, see solution 1038 at
      http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-217.html

      Delete
  71. Please tell me the answer for oct/nov 2009 variant:41 Q2

    ReplyDelete
    Replies
    1. See solution 1103 at
      http://physics-ref.blogspot.com/2016/03/physics-9702-doubts-help-page-236.html

      Delete
  72. Admin, please tell me about any website for chemistry. I really need help!

    ReplyDelete
    Replies
    1. Try to the chemistry version of this site:
      http://chemistry-ref.blogspot.com/

      Currently it's not being updated though. We need people who can participate.

      Delete
    2. Is there hope for the Chemistry blogspot being updated any time soon?

      Delete
    3. It depends. May be if some people wish to participate. But I don't think I would be able to do it on my own right now.

      Delete
  73. I need help in A level physics paper 5.Please add solved pastpapers for paper 5 or atleast tell me about any website where I can get help.

    ReplyDelete
    Replies
    1. Sorry, but I don't think it's going to be possible right now.

      Delete
  74. dear admin i beg you to consider the update for chemistry as this is what is required right now please get it done before the end of the year or could you give us any date please chemistry is also tough we need help thankyou

    ReplyDelete
    Replies
    1. Sorry, unless someone else proposes that he'll help update it.

      I'm quite busy right now and as you can see, even the physics blog is not being updated as regularly as before.

      Delete
  75. can you please help with 9702/11/MJ/11 question 27? Thanks!!

    ReplyDelete
    Replies
    1. see q753 at
      http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-152.html

      Delete
  76. Aoa this site is very helpful. It's a blessing fr all students. May God bless yu. Lots of prayers.
    btw I hav a of questions if you'd help out i'll be grateful.
    9702/23/m/j/10
    question 2 and 3

    ReplyDelete
  77. Can you tell me what is the purpose of specimen paper?

    ReplyDelete

If it's a past exam question, do not include links to the paper. Only the reference.
Comments will only be published after moderation

Currently Viewing: Physics Reference | Physics 9702 Notes | Worked Solutions for Past Papers