Physics 9702 (A-Level) Notes & Worked Solutions for Past Exam Papers
This page contains links to notes for the different chapters of the 9702 Physics syllabus (AS and A-Level) as well as worked solutions (explanations + details) for past exam papers. You may clear any of your doubts at the respective pages.
IF YOU ARE USING THE ANSWERS PROVIDED BY THIS SITE ON OTHER WEBSITES, PLEASE PROVIDE A LINK TO THE SPECIFIC PAGES OF THIS SITE
More notes and worked solutions will be added soon. Be sure to check again frequently.
Some solutions are temporarily displayed here until solutions for the complete paper is available later.
Physics 9702 (A-Level) Guide
Recommended books | Syllabus 2016 Changes |
Exam Structure | Exam Tips | Skills to be tested? | Details of Topics |
A-Levels to MCAT Guide
Physics 9702 (A-Level) Notes
Graphs:
Physics Graphs Basics 1 – Coordinates of Points | 2 - Nature of Gradients |
Units - Base (Fundamental) and Derived | Homogeneity
Uncertainty - no. of significant figures (Check Solution 1022)
Adding vectors graphically (Check Solution 703)
Types of Forces - Gravitational, Electric, Frictional, Viscous drag and Upthrust
Weightlessness (Check Solution 989)
Springs in series and in parallel (Check solution 925)
Circular motion in a vertical plane
Derive escape velocity (Check Solution 338)
Kepler's 3rd law of Gravitation (Check Solution 948)
Concept of 'Internal Energy' + examples (Check Solution 588)
Diffraction of water water in ripple tank (Check Solution 858)
How to draw waves with a phase difference? (Check Solution 318)
Ideal diode (Check Solution 675)
Quantisation of Charge (Check Solution 727)
Specific charge (Check Solution 971)
Binary numbers (Check Solution 555)
ADC and DAC: Reproduction of an input signal (Check Solution 667)
Physics 9702 Summary notes (by Zubair Junjunia, Emir Demirkhan & Saif Asmi)
AS:
1. Physical Quantities and Units | 2. Measurement Techniques | 3. Kinematics | 4. Dynamics | 5. Forces |
Complete A-Level Physics 9702 notes for syllabus 2015 (Credit: Neha of India)
Physics 9702 (A-Level) Worked Solutions for Past Papers
IMPORTANT: More recent papers (as from 2016) will be made available at this new link: Physics 9702 Past Exam Paper Worked Solutions as from 2016.Year 2015
November 2015 Paper 11 Worked Solutions | A-Level Physics 9702
November 2015 Paper 12 Worked Solutions | A-Level Physics 9702
November 2015 Paper 13 Worked Solutions | A-Level Physics 9702
November 2015 Paper 21 Worked Solutions | A-Level Physics 9702
November 2015 Paper 22 Worked Solutions | A-Level Physics 9702
November 2015 Paper 23 Worked Solutions | A-Level Physics 9702
Paper 41 & 42
November 2015 Paper 43 Worked Solutions | A-Level physics 9702
June 2015 Paper 11 Worked Solutions | A-Level Physics 9702
June 2015 Paper 12 Worked Solutions | A-Level Physics 9702
June 2015 Paper 13 Worked Solutions | A-Level Physics 9702
June 2015 Paper 21 Worked Solutions | A-Level Physics 9702
June 2015 Paper 22 Worked Solutions | A-Level Physics 9702
June 2015 Paper 23 Worked Solutions | A-Level Physics 9702
June 2015 Paper 41 & 43 Worked Solutions | A-Level Physics 9702
June 2015 Paper 42 Worked Solutions | A-Level Physics 9702
Year 2014
Past Exam Paper November 2014 Paper 11 & 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2014 Paper 43 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 41 & 43 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2014 Paper 42 Worked Solutions | A-Level Physics 9702
Year 2013
Past Exam Paper November 2013 Paper 11 & 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 21 & 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 23 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2013 Paper 43 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 13 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2013 Paper 23 Worked Solutions | A-Level Physics 9702
Paper 41 & 43
Past Exam Paper June 2013 Paper 42 Worked Solutions | A-Level Physics 9702
Year 2012
Paper 11 |
Past Exam Paper November 2012 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2012 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2012 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2012 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2012 Paper 22 Worked Solutions | A-Level Physics 9702
Paper 41 & 43
Past Exam Paper June 2012 Paper 42 Worked Solutions | A-Level Physics 9702
Year 2011
Past Exam Paper November 2011 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2011 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2011 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2011 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2011 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2011 Paper 42 & 43 Worked Solutions | A-Level Physics 9702
Year 2010
Past Exam Paper November 2010 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2010 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2010 Paper 41 & 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2010 Paper 22 Worked Solutions | A-Level Physics 9702
Paper 41
Past Exam Paper June 2010 Paper 42 & 43 Worked Solutions | A-Level Physics 9702
Year 2009
Past Exam Paper November 2009 Paper 11 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 12 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2009 Paper 42 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 21 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 22 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2009 Paper 4 Worked Solutions | A-Level Physics 9702
Year 2008
Past Exam Paper November 2008 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2008 Paper 2 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2008 Paper 4 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2008 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2008 Paper 2 Worked Solutions | A-Level Physics 9702
Year 2007
Past Exam Paper November 2007 Paper 2 Worked Solutions | A-Level Physics 9702
Past Exam Paper November 2007 Paper 4 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2007 Paper 1 Worked Solutions | A-Level Physics 9702
Past Exam Paper June 2007 Paper 2 Worked Solutions | A-Level Physics 9702
Year 2005
Past Exam Paper November 2005 Paper 2 Worked Solutions | A-Level Physics 9702
Year 2004
Past Exam Paper June 2004 Paper 2 Worked Solutions | A-Level Physics 9702
Question:
can you tell me if i am reading a
volume on a cylinder.....
what error may occur?
and what are the possible
improvements?
Explanation:
The measurements to be made are that
of the diameter and the length of the cylinder using a vernier caliper (for
both).
So, it is obvious that you should
know how to handle and record measurements from a vernier caliper. Also, handle
the caliper with care and take the necessary precautions (do not squeeze the
object, insert object perpendicularly (not diagonally), …)
A possible error that may arise is
zero error. This can be prevented by first bringing the jaws of the caliper
together, before taking any measurements, and verify whether the zero mark of
the vernier scale coincide with the zero mark of the main scale. If it does
then you may record measurements directly. If not, then apply the appropriate
correction before recording the measurements.
Measurements of the diameter should
be taken at different positions (at least 3) along the cylinder and an averaged
value can be calculated. The same is done for the length (you can take 2 or 3
measurements).
Question:
Proper definition for a projectile?
Explanation:
An object upon which the only force
that acts on it is gravity (that is, other forces such as air resistance is
negligible) is called a projectile.
In 1-dimenion motion, an example of
a projectile is an object thrown vertically upward (neglecting air resistance).
This object would have a constant downward acceleration. The path of this
object is along a straight line.
In 2-dimensions, a projectile can be
an object thrown at an angle to the horizontal with a constant velocity. This
object would have a constant horizontal component of velocity, while its
vertical component would be subject to a constant downward acceleration (due to
gravity). Again, air resistance is negligible. The path of this object is a
trajectory.
June 2014 p12
ReplyDeleteJune 2014 P12 & all the June 2014 papers' solutions will be added a little later (but of course before the November exams). But if you are having specific problems, you may asked about it here until the worked solutions are provided.
DeleteBe sure to check later.
In the meantime, more worked solutions of the earlier papers will be provided.
9702_w09_qp_12 question 8 and 30.
ReplyDeletethank you :)
8 – Ans: A. For elastic collision, velocity of approach (before collision) = velocity of separation (after collision). velocity of approach = u + u = 2u. Only answer A gives velocity of separation = 2u.
Delete30 – Ans: C. Rate of energy transfer = Power. P = VI = I2R. Answer A gives P = 4Js-1. B gives 32Js-1. C gives 16Js-1 and D gives 256Js-1. So, ans = C.
(the superscripts do not seem to work here but I think you can understand)
Aoa this site is very helpful. It's a blessing fr all students. May God bless yu. Lots of prayers.
ReplyDeletebtw I hav a couple of questions if you'd help out i'll be grateful.
9702_w07_qp_11 question 29 and 31
9702_w05_qp_11 Q33
9702_s05_qp_11 Q32
9702_s11_qp_22 Q5
Note: y^2: means y squared
Delete9702_w07_qp_1 question 29 and 31
29 – Ans: D. P = VI = V^2/R. Px = Py. So, (12x12) / Rx = (6x6) / Ry. Rx / Ry = 144 / 36 = 4.
31 – Ans: A. R = ρL/A. A = π(d/2)^2. So, R∝ L / (d/2)^2. Rq ∝ L / (d/2)^2 = 4L / d^2. Rp ∝ 2L / (2d/2)^2 = 2L / d^2. So, Rp / Rq = 2 / 4 = 0.5.
For these type of questions, you need to write them down. Do not do it in your mind.
9702_w05_qp_1 Q33
33 – Ans: D. Strain = e/ L where e is the extension and L is the original length. An increase in the strain (extension) means increasing the length and this also causes the cross-sectional area to decrease. Now, R = ρL/A, so R increases
9702_s05_qp_11 Q32
32 – Ans: C. charge, Q = It so I = Q/t = 10. Now, the total charge Q = ne where n is the number of electrons and e is the charge of an electron = 1.6x10^-19C. So, ne / t = 10 and n /t is the number of electrons passing a given cross-section = 10 / (1.6x10^-19) = 6.3x10^19.
[No need to use area here.]
9702_s11_qp_22 Q5
This is June 2011, which is already posted. Look at the links above.
Hope it is clear to you
Nov 09 Paper 41 8(c)(ii)
ReplyDeleteYou need BE per nucleon. Tritium contains 3 nucleons and deuterium contains 2 nucleons. Values given in table are for BE 'per nucleon'.
So LHS of equation = 2(1.12) + 3x
where x is BE per nucleon for tritium.
Similarly, RHS of equation = 4(7.07) – 17.7
since helium contains 4 nucleons.
Solving gives x = 2.78MeV
hi
ReplyDeletecan i have work exam paper for year 2007 to 2010
?
the 2010 and earlier papers will be published next.
ReplyDeletecheck again later
in how mush time?
DeleteI`ll publish one every 3 days, i think (at the time of writing)
DeleteThis may change though
can u plz publish them
ReplyDeletei really need help
if you are having SPECIFIC questions on the earlier papers, I will try to help as soon as possible. But plz, do not ask for all of them
Delete9702_w08_qp_1 question 24.
ReplyDeleteThanks in advance :)
24 – Ans: D.
DeleteAmplitude is the maximum displacement. Amplitude of Y is half that of X (as can be clearly seen in diagram), so amplitude of Y = 4cm. Frequency, f = 1 / T where T is period. For X, period = 1 / 100 = 0.01s. As seen from diagram, period of Y is one third that of X (3 oscillations occurs for the same amount of time), so period of Y = 0.01 /3. Frequency of Y = 1 / [0.01/3] = 300Hz. (or you could directly obtain the frequency to be 3 times that of X if you understand the concept of frequency well)
Question (November 2000 paper 1 question number 27):
ReplyDeleteAn early experimenter, working in other than Si units, obtained the following ten values for the magnitudes of the changes on small oil drops:
9.82, 19.64, 39.28, 39.28, 34.37, 19.64, 19.64, 29.46, 19.64, 39.28.
What value do these results suggest for the magnitude of the charge of the electron as measured in these units?
A 2.45
B 4.91
C 9.82
D 19.64
Explanation:
We are looking for the charge of an electron. The oil drop may contain 1 electron, or 2 or 3 or 4, (an integer) ... but not 1.5, 2.5, ... (we obviously cannot have half an electron). The charge of the oil drop would be that integer times the charge of an electron. From this info, we can eliminate all the values except the smallest one since the other need to be product of an integer with the charge of an electron. [D is eliminated]
Now we look at the smallest value, which is 9.82. If we ASSUME that it IS the charge of an electron, then all others should be integral multiples of it. (That is, taking any of the values divided by the smallest one would give an integer. e.g: 19.64/9.82 = 2 , ...). If we try, all of them would give integers except 34.37 which gives 3.5 (not an integer). [C is eliminated]
So, 9.82 cannot be the charge of an electron. We now take 4.91. This is half 9.82, so every value which were integral multiple of 9.82 will also be an integral multiple of 4.91. In this case, even 34.37 gives an integral (=7) when divided by 4.91. So, every value gives an integer with 4.91, making it the correct answer.
But why is ans A incorrect? It is half 4.91, so it will also give integer with all the values?? But then, if we take another ans which = 2.45/2, it will also give integers! So, what we need is what is called Greatest Common Factor or Highest Common Factor
Question: Test homogeneity
ReplyDelete1. P=rho*g*h......show if this is a homogeneous equation
2.E=mc^2......show if this is a homogeneous equation
1.
Pressure, P = Force / Area = [mass][acceleration] / [area] = kg ms^-2 m-2 = kg m^-1 s^-2
Now, density, rho = mass / volume = kg m^-3
So, P = rho*g*h = kgm^-3 ms^-2 m = kg m^-1 s^-2
So, homogeneous
2.
E = mc^2
Energy, E = Force x distance = kg ms^-2 m = kg m^2 s^-2
E = mc^2 = kg (ms^-1)^2 = kg m^2 s^-2
So, homogeneous
Question: November 2003 Paper 2 Question 2(b)
ReplyDelete2 situations where a body of constant mass may experience a change in its apparent weight:
Situation 1:
When the gravitational field strength changes {when the field is not constant – weight, W = mg so if g changes, W also changes. Also weight of a person on Moon is different from weight of same person on Earth}
Situation 2:
When (the body is immersed in a fluid) and then the fluid (surrounding the body) is changed {the resistive force (upthrust force) from the liquid would change. SO, there is now a resultant acceleration, a. Weight is then given by ma}
Situation 3:
When the body is accelerated in a lift {for same reason as in the fluid – there is a resultant acceleration. When the lift is accelerating downwards, weight is greater and if the lift is accelerating upwards, weight is less}
Please note the following:
DeleteWeight is the downward force exerted on a body by Earth's gravity while apparent weight is the normal reaction (upward) to weight. So, weight is constant while the apparent weight may vary. So, in situation 2, it's not 'weight is then given by ma', but the apparent weight.
Also, situation 3 has been wrongly explained. Instead of weight, apparent weight should be used and when the lift is accelerating downwards, the apparent weight is less than the weight (since the resultant force on him is downwards,) and when accelerating upwards, the apparent weight (on him) is greater than the weight.
Sorry for this mistake
can someone help me plz with the may/june 2011 paper 41 question numbers 10 and 11
ReplyDeleteSolutions are temporarily available above
DeleteHere are solutions for some specific questions of Nov 11 P13:
ReplyDelete5 – Ans: B. Expanding the left hand side gives 3L + a^2 L/P. For equation to be homogeneous (and hence correct), the units should be the same on both sides of the equation and the units for 3L = units for a^2 L/P. L has unit m (since it is a distance), so all the different parts should have an overall unit of m. Considering the a^2 L/P: [m^2][m] / [P] = m. So, [P] = [m^3] / [m] = m^2. Now for QT^2 sinθ: sinθ has no units. So, [Q][s^2] = m giving [Q] = ms^-2.
21 – Ans: B. For any specific material, the Young modulus is always constant. So, here E is constant for this particular type of steel since the SAME steel is used.
25 – Ans: B. (I’m using capital L so that you may do not confuse between one (1) and small letter L (l)) For elastic compression, F = kΔL. Now, consider the Young modulus , E= stress / strain = (Force/Area) / (extension/original length). E α (original length) / (Area x extension). E α L / (L^2 x ΔL). E α 1 / (L x ΔL). So, ΔL α 1 / (E L) giving ΔL α 1 / L.
30 – Ans: A. This is basic knowledge. Both pipes will give a stationary wave.
37 – Ans: B. The potential difference, V across any loop is the same. V = IR, so when resistance is 2R, current should be I/2 so that pd = (I/2)(2R) = IR = V. Similarly, when resistance is 3R, current should be (I/3) so that pd = (I/3)(3R) = IR = V.
Solution for June 2011 Paper 13 Q19:
ReplyDelete19 – Ans: D. Total mass = mass of water + mass of alcohol = 1.5(1000) + 0.5(800) = 1900kg. Density = mass / volume = 1900 / 2 = 950kgm^-3.
Explanations for November 2011 Paper 51 Question 2 (c)(iv) & (d)(i), (ii) are temporarily available above
ReplyDeletehi can u plz give some explanations for the 9702_s14_qp_12. Number 14,21,24 28,32 and 36.
ReplyDeletePlz upload the work solution as quick as u can !!!
9702 June 2014 Paper 12 Worked Solutions are now available
DeleteExplanations for November 2011 Paper 11 Question 16, 26, 28 and 29 are temporarily available above.
ReplyDeleteNovember 2003 Paper 1 Q35:
ReplyDelete35 – Ans: D. Electric field is from positive to negative. So, field lines should be towards the point charge –q. Field lines are straight lines here.
November 2002 Paper 1 Q35:
ReplyDelete35 – Ans: D.
Let resistance of wire XY = W and resistance of variable resistor = R. From potential divider equation, potential difference across XY = V [W / (W+R)]. As R is increased, the pd across the wire decreases. Now, for galvanometer to show zero deflection, resistance of wire should be increased. Resistance of wire = ρL/A. So, length of wire, L (between X and N) should be increased. So, position of moveable contact should be nearer to Y.
9702/2007 paper1 November question 25 please explain and write the solutions. Thank you ! :)
ReplyDelete25 – Ans: B. dsinθ = nλ. When n = 3 (third order), θ = 45 deg. So, dsin(45) = 3λ. So, d / λ = 3 / sin(45). For highest order if diffracted beam, angle should be less than 90 deg. So, consider angle θ = 90 deg. dsin(90) = nλ giving n = (d / λ) sin(90) = [3sin(90)] / sin (45) = 4.24. n should be an integer which is less than this. So, n = 4.
DeleteDo you mind explaining why 9702/11/ON/2009 question 9, 13, 14,15,17,21,23,26 and 40. Thank you!
ReplyDeleteOK. But you may not obtain them today. I hope this is not a problem
DeleteNovember 2009 Paper 11 solutions are available
Deletenov 07
ReplyDeletepaper 2
no... 4,5,6
OK. But it will not be the next post since there's another request first
ReplyDeletejune 2010 paper 42
Deleteno.... 6,10,11
and when are publishing the june 14 p42?
Its Paper 4 9702/O/N/2007 Qn 1. b) ii) Can you pls explain it in detail? tq :D
ReplyDeletedetails have been added at the page
Delete9702/21/ON/10 Q6(b) I know it's quite simple but can you explain to me? Part (i) n (ii) other than getting the answers by theory, is there a way I can work it out?
ReplyDelete9702/21/ON/10 Q6(b) I know it's quite simple but can you explain to me? Part (i) n (ii) other than getting the answers by theory, is there a way I can work it out?
ReplyDeletelook at qu2 at
Deletehttp://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-1.html
9702/21/M/J/11 Q4 b(ii) and Q5 (b)
ReplyDeletequestions correspond to qu3 and 4 at
Deletehttp://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-1.html
9702/21/MJ/13 Q5(C) explanations. How to get the answer in marking scheme (5 maxima and 6 minima) ? Thanks
ReplyDeleteit's explained as qu25 at
Deletehttp://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-4.html
9702/02/M/J/05 question 6 (b)(i)
ReplyDeletecheck qu28 at
Deletehttp://physics-ref.blogspot.com/2014/10/physics-9702-doubts-help-page-4.html
9702/22/ON/09 Q6(C)
ReplyDeleteI'll post the worked solutions for this paper soon. Check again
Deleteworked solutions now available
Deletehi, can you please draw me the graph on w05 paper 4 q6(c)(ii) ?
ReplyDeleteCheck qu 34 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-5.html
I've explained the question there
9702/22 MJ 2009
ReplyDelete5)(c) can you explain why? I don't understand the marking scheme.
And 9702/ 21 MJ 2010
4)(c) and 4)(d) I also don't understand the marking scheme either. Thank you :)
Links for both papers are available above. If you still don't understand, specific your doubts at the respective pages
DeleteCan you post the working solutions for 9702 2010 p23 nov
ReplyDeleteAnd explain question 3 ,5(b) and 6(b)(II) 1 thank you
9702/02/MJ/08 Q6 step by step solution please...
ReplyDeleteIt's available as question 45 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-8.html
9702/22/MJ/13 Q5(iii) You have provided answer. But I do not understand why horizontal line through PQ. Please explain. Thanks!
ReplyDeleteI have included a link for the explanation at the page. Read it.
DeleteGot it.. TY! :)
DeleteCan you upload your working solutions for 2010 MJ P23 thank you :)
ReplyDeletejune 09 p12 no15?
ReplyDeletecheck solution 64 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-12.html
do you have sample answer for p5?
ReplyDeleteplanning?
currently none? but i once solved parts of 2 questions. they are available above
Deleteim having trouble to decide how many significant figure my answer should be. in the marking scheme it does not mention how many significant figures however it only shows one answer sometimes 2 significant and sometimes 3
ReplyDeletecan you tell me to which question(s) you are referring? which year? I'll try to help based on them
Deletefor example in may june 2008 paper 2 question 3 why is the acceleration given to 2 significant figures but in c(i) it is given to 3 significant figures
DeleteCheck question 79 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-15.html
if you are still unsure, clear your doubts there
Hi, could you explain the may/ june 2013 paper 11 Q 18, 35
ReplyDeleteQ18 is explained as solution 93 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-17.html
the other one will be explained later
Q35 is explained as solution 100 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html
Oct/Nov 2002 Q15, 17, 28, 35 and 37.
ReplyDeleteQ35 is explained as solution 99 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-18.html
the others will be explained later
Q15 is explain as solution 103 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html
Q17 is explained as solution 109 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-21.html
Q28 is explained as solution 118 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-22.html
Q37 is explained as solution 122 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-23.html
can someone help me wiz zis question plz.
ReplyDeleteMonochromatic light of wavelength 690 nm passes through a diffraction grating with 300 lines per mm, producing a series of maxima on a screen.What is the greatest number of maxima that can be observed
It's from November 2012 Paper 12 Q30 and has already been explained. Use the corresponding link for the paper above.
Deletethanks that has help me a lot
DeleteCan someone help me with q7b) in M/J 07 and O/N 05 Q 6c)ii) and M/J 02 q6a) ?
ReplyDeleteNov 2005 Paper 2 worked solution is available at
Deletehttp://physics-ref.blogspot.com/2014/09/9702-november-2005-paper-2-worked.html
(check links above)
the others will be added soon
Can someone look at q5a)ii) 1. in MJ/2010/41? How to justify whether the expression is valid? Pls help me with the graph in MJ/2002 paper 4 q6a) and MJ/2007 paper 4 q7b)?
ReplyDeleteFor the MY/ 2007 Paper 4 Qu 7
Deletecheck qu 106 at
http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-20.html
I'll try to add the others as soon as possible
9702/12/ON/11 Q 33, 37 and 38 please.
ReplyDeleteQ33 has already been solved. Check ad
Deletehttp://physics-ref.blogspot.com/2014/08/9702-november-2011-paper-12-worked.html
The others will be explained soon
Q37 has also been added
DeleteQ38 has been added
Delete9702/11/MJ/13 Q 14, 18, 35. Thanks!
ReplyDeleteQu18 is available as solution 93 at Physics Doubts | Help Page 17
Delete(http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-17.html)
and Qu35 is available as solution 100 at Physics Doubts | Help Page 19
(http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-19.html)
Qu14 will be added soon
Q35 why do we take [1.5 / (1.5 + 0.75)] at the second loop and not [0.75 / (1.5 + 0.75)]?
DeleteQu14 is available as solution 116 at Physics Doubts | Help Page 22
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-22.html
For Qu 35, some notes have been added. Read them carefully
DeleteThanks for the extra notes ! ;)
Delete9702/12/ON/09 Q12 (Don't know how to get tension in top of belt), Q13, Q14, Q39 Don't understand the effect of gold nucleus on alpha particles)
ReplyDeleteQu 12 has been added at the November 2009 Paper 12 Worked Solutions link available above. Others will be added soon
DeleteQu13 has also been solved
Deletenov 2011 p12 no29?
ReplyDeleteDetails for this question has been added at the page
Deletecould u pls look into explaining me solns to 13/m/j/13 no. 14 &21
Deletei need them desperately
Qu 14 has been explained as solution 128 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-23.html
9702/01/MJ/09 Q7, Q13 (After looking at answer I know how to get it, but don't understand the concept of the whole system how it works), Q18. TY!
ReplyDeleteQ7 has been solved as solution 150 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html
Others will be added soon
Need help on 9702/13/ON/13 Q15, 32, 33, 37. Thanks in advance!
ReplyDeleteQ15 explained as solution 134 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-24.html
Others will be added later
Qu32 explained as solution 141 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-25.html
Q33 explained as solution 153 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-26.html
could u pls explain me the answer of 01/m/j/09 q15
ReplyDeleteIt's explained as solution 64 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-12.html
June 2012 paper 13 question 8, 9, 10 ,13 thanks yea!
ReplyDeletehi can you plz explain November 2008 p12 number 1 and 32
ReplyDelete11/M/J/10 q12 pls.......
ReplyDeleteit's explained as 175 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html
november 2010 paper 12 q12
ReplyDeletethe question is explained as solution 176 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html
w_10_qp_12
ReplyDeleteq25
question is explained as solution 132 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-24.html
hi i need help for 9702/11/MJ/12 ques 12
ReplyDeleteThanks!
the question is explained as solution 178 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html
need help on 9702/11/M/J/12 ques 12
ReplyDeleteThanks!
If i come out of the exam fully satisfied with my performance then i will not hesitate to fully dedicate my success to you. And once again thanks >>>
ReplyDeleteHere are my doubts
ReplyDelete1/O/N/02 Q.14
01/M/J/03 Q.10
03/M/J/03 Q.1(g)
01/O/N/03 Q.5,6,11
01/M/J/04 Q.9,21,23,25,26,27,28
02/M/J/04 Q.2(b),Q.6(b) (Demonstration of graph and lines are required)
01/O/N/04 Q.5,13,14
01/M/J/05 Q.5,13,14,16,22,24,25
02/M/J/05 Q.5(b)(i)(ii)
01/O/N/05 Q.11,16
Some questions are solved at
Deletehttp://physics-ref.blogspot.com/2014/12/physics-9702-doubts-help-page-32.html
More will be added soon. If it's on a different page, I'll let you know through the replies to this comment
Note: please post your future doubts at the doubts pages or the respective worked solution pages as asked above. Comments here will no longer be published. Hope you will co-operate. Thanks
More solutions have been added
Deletejust wanted to thankyou i got 90 in my as physics and it was largely for your help ^_^
ReplyDeleteso thanks once again
Can you kindly solve 9702/01/M/J/03 Q20? Thank you!
ReplyDeleteSee solution 742 at
Deletehttp://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-150.html
NOTE:
DO NOT POST ANY MORE COMMENTS HERE PLEASE.
Use the other pages.
COMMENTS HERE WILL NO LONGER BE CONSIDERED
This Blog is my Life Saviour. To a girl who always had difficulties with Physics, this has been of great help and I can't describe how grateful I am to have found this blog!
ReplyDeletethnxx a lot.your blog is amazing.
ReplyDeletecan u plzz help with qtn no.6 m/j 2008 p2
ReplyDeletethis blog is amazing :)
ReplyDeleteCan you please tell me the answers for oct/nov 2009 9702 variant:41
ReplyDeleteQ2 Q3(part 1) Q10 Q11.
(Please do reply)
For Q10, see solution 1038 at
Deletehttp://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-217.html
Please tell me the answer for oct/nov 2009 variant:41 Q2
ReplyDeleteSee solution 1103 at
Deletehttp://physics-ref.blogspot.com/2016/03/physics-9702-doubts-help-page-236.html
Admin, please tell me about any website for chemistry. I really need help!
ReplyDeleteTry to the chemistry version of this site:
Deletehttp://chemistry-ref.blogspot.com/
Currently it's not being updated though. We need people who can participate.
Is there hope for the Chemistry blogspot being updated any time soon?
DeleteIt depends. May be if some people wish to participate. But I don't think I would be able to do it on my own right now.
DeleteI need help in A level physics paper 5.Please add solved pastpapers for paper 5 or atleast tell me about any website where I can get help.
ReplyDeleteSorry, but I don't think it's going to be possible right now.
Deletedear admin i beg you to consider the update for chemistry as this is what is required right now please get it done before the end of the year or could you give us any date please chemistry is also tough we need help thankyou
ReplyDeleteSorry, unless someone else proposes that he'll help update it.
DeleteI'm quite busy right now and as you can see, even the physics blog is not being updated as regularly as before.
can you please help with 9702/11/MJ/11 question 27? Thanks!!
ReplyDeletesee q753 at
Deletehttp://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-152.html
Aoa this site is very helpful. It's a blessing fr all students. May God bless yu. Lots of prayers.
ReplyDeletebtw I hav a of questions if you'd help out i'll be grateful.
9702/23/m/j/10
question 2 and 3
Can you tell me what is the purpose of specimen paper?
ReplyDeleteIt is provided whenever there has been mayor changes in the syllabus (like that of 2016). It provides examples on how the paper and its question may look like in the coming exams.
Deleteaoa. can u please explain oct nov 2006 p1 q11
ReplyDeleteAssalamualaikum,
ReplyDeleteWould u please give me any advise for my upcoming multiple choice exam
Can u give me the work and solutions for May June 2008 paper 2 question 6b?
ReplyDeletejust one to take a moment to thank you, this is seriously such great help for all students. thank you ! :)
ReplyDeletecan you please help me with 9702/0/N/2014/12 number 8?
ReplyDeleteThanks to this amazing website I got A in both A's and A level in physics that is without taking any tuition or even going to school... This website really deserves an applause...
ReplyDeletePlease kindly help with
ReplyDeleteM/J/16 12 q15
JazakAllah Khairen Katheeran
May Allah عز وجل reward you immensely.
THANKYOU SO MUCH FOR THIS WEBSITE!!! God bless you. Also i would really appreciate it if recent years worked solutions like 2016 and 2017 are added too. THANKYOUU
ReplyDeleteDear Sir. Could you help out with 9702/11 Oct/Nov 2017 Question 8, pls?
ReplyDeleteThe three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to the air resistance and the upthrust force.
The hot-air balloon descends vertically at constant speed. The force of air resistance on the balloon is F.
Which weight of material must be released from the balloon so that it ascends vertically at the same constant speed?
Ans: B) 2F
A mass of 160 g of water at 100 °C is poured into the hollow. The water has specific
ReplyDeleteheat capacity 4.20 kJ kg–1 K–1. Some of the ice melts and the final mass of water in the
hollow is 365 g.
(i) Assuming no heat gain from the atmosphere, calculate a value, in kJ kg–1, for the
specific latent heat of fusion of ice.
9702/13/O/N/15 Question 35
ReplyDeleteThank you very much for this page. I am so happy to have found this page. Jazzakumulahi khairan!
ReplyDeleteCould you pls solve q.9 p1 oct-nov 2002 one. I cant understand it. Tysvm
ReplyDeletego to
Deletehttps://physics-ref.blogspot.com/2018/11/two-markers-m1-and-m2-are-set-up.html
Hi, I am having difficulty getting the answer for 9702/01/M/J/04 Q9. Can you please solve and explain.
ReplyDeletesee solution 200 at
Deletehttp://physics-ref.blogspot.com/2014/12/physics-9702-doubts-help-page-32.html
June 2005 p4 Q6..?
ReplyDeleteGo to
Deletehttps://physics-ref.blogspot.com/2018/12/fig-62-shows-variation-with-time-t-of.html
9702 o/N 16/p11/Q11
ReplyDeletesee
Deletehttp://physics-ref.blogspot.com/2018/10/9702-november-2016-paper-11-13-worked.html
solved solutions 9702/11/16 available?
DeleteGO to
Deletehttp://physics-ref.blogspot.com/2018/09/physics-9702-past-exam-paper-worked.html
is worked solution mj 16 p11 for physics available?
ReplyDeleteGO to
Deletehttp://physics-ref.blogspot.com/2018/09/physics-9702-past-exam-paper-worked.html
The sides of a cube are measured with calipers. The measured length of each side is (30.0 ± 0.1)mm. The measurements are used to calculate the volume of the cube. WHAT IS THE PERCENTAGE UNCERTAINITY IN THE CALCULATED VALUE OF THE VOLUME.
ReplyDelete9702/s18/qp11
Go to
Deletehttp://physics-ref.blogspot.com/2019/01/the-sides-of-cube-are-measured-with.html
ON 2002 P2 Q7 part b(i)
ReplyDeleteGo to
Deletehttp://physics-ref.blogspot.com/2019/01/the-resistors-are-of-resistance-15-and.html
So I used in part(ii)the answer of part a so i got I=8.88÷60=0.148A
DeleteSo Energy consumed in 15 ohm resistor would beE=I^2×R×t(time)
=(0.148)^2×(15)×(1.3×10^5)
So answer i got is 42712.8 which is not close to correct answer.
I think my method is right but answer doesn't justify that.
Please help me through it!!!!
We cannot directly use Ohm’s law to obtain the current. I = V / R
DeleteWe have not been told that the internal resistance of the battery is negligible. So, the total resistance is NOT 15 + 45 = 60Ω
the same applies for the next part.
So Electric field MCQs are so hard.I went through some of them and i have absolutely no idea what i saw.Unlike the paper 2 which is straoght forward for Electric fields.MCQs are very hard.So pleease can you guide me through it or at least please make notes for the rules of making electric fields??
ReplyDeleteThank you!!!
You may go through the examples at
Deletehttp://physics-ref.blogspot.com/search/label/Electric%20fields
More questions will be added with time.
As for notes, I don't think this would be any time soon.
So, see the solutions and try to understand the examples
A O A!!!So the problem is that in V-I graph why does not the gradient of graphy gives resistance???
ReplyDeleteIn many past paper qs,examiner has discount the marks for this part like for o/n 2004 Q 6 or MayJune 2010 P23 Q6 b?
Shouldn't its gradient gibe resistance like in velocity -time graph gradient gives acceleration?
I am confused Please help
Wslm.
DeleteFrom Ohm's law, resistance is the ratio of V/I
when dealing with ratio, we only take a single value of V and a single value of I.
when calculating the gradient, we need to use 2 points - that is, 2 set of values of V and I.
But the resistance cannot be found in this way. We need to use a single value of V and I.
To find the resistance from the V-I graph, consider a single point. The x-coordinate is I and y-coordinate is V.
Resistance = y-coordinate / x-coordinate
not the gradient
Kindly solve ON/15-43 Q.11?
ReplyDeletego to
Deletehttp://physics-ref.blogspot.com/2019/02/an-x-ray-source-is-placed-on-one-side.html
Kindly solve MJ12-43Q.10?
ReplyDeletego to
Deletehttp://physics-ref.blogspot.com/2019/03/a-student-designs-electronic-sensor.html
the pictures on your website are not loading kindly check
ReplyDeletemay be it's a problem with your internet connection.
Deletetry again
No Sir All other websites are working and this too but only pictures are not loading(have checked by connecting with neighbour's wifi as well)
ReplyDeleteIt's fine on my end
DeleteS12 P41 Q7 please
ReplyDeletego to
Deletehttps://physics-ref.blogspot.com/2019/08/9702-june-2012-paper-41-43-worked.html
W2018 P23 Q6(c) please
ReplyDeletego to
Deletehttp://physics-ref.blogspot.com/2019/09/the-diameter-of-wire-st-varies-linearly.html
please solve q5/s08/04
ReplyDeletego to
Deletehttp://physics-ref.blogspot.com/2019/12/a-capacitor-c-is-charged-using-supply.html
hi, can you explain nov2018 p23 qu 7(b)(i)?
ReplyDeleteand where can i find solution to this question
Please solve q 26 of varient 2 p1 summer 2019
ReplyDelete