9702 November 2008 Paper 2 Worked Solutions | A-Level Physics
Paper 2
Question 1
(a)
Current in wire is I. Charge Q
passes 1 point in wire in time t.
(i)
Relationship between I, Q and t:
Q = It
(ii)
Which are base quantities:
I, t
(b)
Current in wire is due to electrons,
each with charge q that move with speed v along wire. There are n of these
electrons per unit volume. For wire having cross-sectional area S, current I
given by I = nSqvk
where k is a constant.
(i)
Units of I, n, S, q and v in terms
of base units:
Base units:
I: A
n: m-3
S: m2
q: As
v: ms-1
(iii)
Considering homogeneity of equation,
value of k:
I = nSqvk
[A] = [m-3][m2][As][ms-1]k
e.g. For m: 0 = -3 + 2 + k
So, k = 1
Question 2
{Detailed explanations for this question is available as Solution 1092 at Physics 9702 Doubts | Help Page 232 - http://physics-ref.blogspot.com/2016/01/physics-9702-doubts-help-page-232.html}
Question 3
(a)
Distinguish between moment of a
force and torque of a couple:
The moment of a force is the product
of the force to the perpendicular distance of the force from the pivot /
axis / point.
The torque of a couple is the
product of (the magnitude of) one force to the perpendicular distance
between the two forces.
(b)
One type of weighing machine, known
as steelyard, is illustrated. Two sliding weights can be moved independently
along rod. With no load on hook and sliding weights at zero mark on metal rod, metal
rod is horizontal. Hook is 4.8 cm from pivot. A sack of flour is suspended from
hook. In order to return metal rod to horizontal position, 12 N sliding weight
is moved 84 cm along rod and 2.5 N weight is moved 72 cm.
(i)
Weight of sack of flour:
(Anti-clockwise moment = Clockwise
moment)
W(4.8) = 12(84) + 2.5(72)
Weight, W = 250N (248N)
(ii)
Why steelyard would be imprecise
when weighing objects with weight of about 25N:
EITHER There is friction at the
pivot OR It would require only a small movement of the weights
Question 4
{Detailed explanations for this question is
available as Solution 416 at Physics 9702 Doubts | Help Page 78 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-78.html}
Question 5
Some smoke particles are viewed
through microscope, as illustrated. Brownian motion is observed.
(a)
Brownian motion is haphazard /
random / erratic / zig-zag movement of (smoke) particles
(b)
Explain why Brownian motion provides
evidence for movement of molecules as assumed in kinetic theory of gases:
Brownian motion is due to unequal /
unbalanced collision rates
(on different faces). (This unequal collision rate is due to the) random motion
of (gas) molecules / atoms
(c)
Smoke from poorly maintained engine
contains large particles of soot. Why Brownian motion of such large particles
is undetected:
EITHER
The collisions with the air
molecules average out. This prevents the haphazard motion.
OR
The particle is more massive /
heavier / has large inertia. So, the collisions cause only small
movements / accelerations.
Question 6
{Detailed explanations for this question is
available as Solution 241 at Physics 9702 Doubts | Help Page 39 - http://physics-ref.blogspot.com/2014/12/physics-9702-doubts-help-page-39.html}
(a)
(a)
Diffraction of a wave is the bending
/ spreading of the wave (into geometrical shadow) when the wave is
incident at an edge / aperture / slit / (edge of) obstacle
(b)
(i)
Experiment that may be used to
demonstrate diffraction of a transverse wave:
Examples for the apparatus:
Laser & slit / a point source
& slit / lamp and slit & slit
A microwave source & slit
Water / ripple tank, source &
barrier
Example for the detector:
A screen
Aerial / microwave probe
A strobe / lamp
What is observed
(ii)
How experiment in (i) may be changed
to demonstrate diffraction of a longitudinal wave:
For apparatus, e.g. loudspeaker, and
slit / edge
For detector, e.g. microphone &
c.r.o / ear
What is observed
Question 7
{Detailed explanations for this question is
available as Solution 409 at Physics 9702 Doubts | Help Page 76 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-76.html}
Question 8
Thoron is radioactive gas. Variation
with time t of detected count rate C from sample of the gas shown. Radioactive
decay said to be random and spontaneous process.
(a)
By reference to radioactive decay,
random process:
In a random process, a nucleus
has a constant probability of decay per unit time / in a given time
(b)
Feature of Fig which indicates that
process is
(i)
Decay process:
The count rate / activity decreases
(ii)
Random:
The count rate fluctuates / is not
smooth
(c)
Second similar sample of thoron
prepared but it is at much higher temperature. Variation with time of count
rate for this second sample is determined. Feature of decay curves for the 2
samples that suggests that radioactive decay is a spontaneous process:
EITHER The (decay) curves are similar
/ same OR The curves indicate the same half-life.
why did u multiply -.85 m s ^ -2 which is already the given acceleration with 9.8
ReplyDeleteLook carefully. The deceleration given is 0.85g, not g.
Delete'magnitude of deceleration of car is 0.85g, where g is acceleration of free fall.'
summer 2008 paper 2 Q.7 pls
ReplyDeleteSee solution 970 at
Deletehttp://physics-ref.blogspot.com/2015/09/physics-9702-doubts-help-page-200.html
In question 2b,what is 22.1m/s?
ReplyDeleteThis would depend on the calculations used. I did not use arrive at this value. But as it was present in the mark scheme I included it.
Delete