Friday, June 19, 2015

9702 November 2014 Paper 23 Worked Solutions | A-Level Physics

  • 9702 November 2014 Paper 23 Worked Solutions | A-Level Physics

Paper 23




Question 2
{Detailed explanations for this question is available as Solution 680 at Physics 9702 Doubts | Help Page 137 - http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-137.html}





Question 3
{Detailed explanations for this question is available as Solution 897 at Physics 9702 Doubts | Help Page 183 - http://physics-ref.blogspot.com/2015/08/physics-9702-doubts-help-page-183.html}





Question 4
{Detailed explanations for this question is available as Solution 953 at Physics 9702 Doubts | Help Page 197 - http://physics-ref.blogspot.com/2015/09/physics-9702-doubts-help-page-197.html}




Question 6
{Detailed explanations for this question is available as Solution 696 at Physics 9702 Doubts | Help Page 141 - http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-141.html}





Explanations have been provided for questions that were found to be more difficult. If you are having other doubts that have not been explained here, you may ask your questions through comments.


14 comments:

  1. Can you help me with question 3

    ReplyDelete
    Replies
    1. Question 3 has now been explained

      Delete
  2. Could you help me with question 4 especially the answer for part D?

    ReplyDelete
  3. j 15 p 23 Ques 5. please...
    thank u in advance ...

    ReplyDelete
    Replies
    1. Check solution 1000 at
      http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-208.html

      Delete
  4. J15p23 ques 1(e)..
    please...

    ReplyDelete
  5. j 15 p23 Ques 1 (e)

    ReplyDelete
    Replies
    1. Check solution 1012 at
      http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-211.html

      Delete
  6. j15p23 Ques 2
    please.

    ReplyDelete
    Replies
    1. Check solution 1019 at
      http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-212.html

      Delete
  7. can you explain on qn 6 why resistance is 5?

    ReplyDelete
    Replies
    1. No current flows in cell Y. So, cell Y can be considered to be short circuited and with C at this position, the circuit can be considered to consist of cell X (with internal resistance 1.0 Ω) and the wire BD (having a resistance of 4.0 Ω as calculated in part (a)).
      Total resistance = 1.0 + 4.0 = 5.0 Ω

      Delete
    2. I see, I guessed so though but I had doubt that the questions are not related. I am very thankful for your help. =)

      Delete

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