9702 June 2013 Paper 12 Worked Solutions | A-Level Physics
Paper 12
1 B 11
D 21 C 31 A
2 B 12
A 22 B 32 C
3 A 13
B 23 B 33 A
4 D 14
D 24 D 34 A
5 C 15
B 25
D 35 D
6 B 16
B 26 B 36 D
7 D 17
C 27 C 37 C
8 B 18
A 28 B 38 C
9 D 19
C 29 C 39 B
10 B 20
D 30 D 40 B
Notes for some specific questions:
1 – Ans: B. Both vectors in A and
both scalars in C and D.
2 - Ans: B. {Detailed explanations for this question is available as Solution 520 at Physics 9702 Doubts | Help Page 101 - http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-101.html}
3 – Ans: A. Cannot be C since the 2
forces are not equal, so the angle of the resultant cannot be 45 degrees.
5 - Ans: C. {Detailed explanations for this question is available as Solution 834 at Physics 9702 Doubts | Help Page 166 - http://physics-ref.blogspot.com/2015/06/physics-9702-doubts-help-page-166.html}
6 - Ans: B. {Detailed explanations for this question is available as Solution 283 at Physics 9702 Doubts | Help Page 47 - http://physics-ref.blogspot.com/2015/01/physics-9702-doubts-help-page-47.html}
8 - Ans: B.
9 – Ans: D.
A strong wind of speed33 m s-1 blows against a wall. The density of the air is1.2 kg m-3. The wall has an area of 12 m2 at right angles to the wind velocity.
11 - Ans: D. {Detailed explanations for this question is available as Solution 829 at Physics 9702 Doubts | Help Page 165 - http://physics-ref.blogspot.com/2015/06/physics-9702-doubts-help-page-165.html}
11 - Ans: D. {Detailed explanations for this question is available as Solution 829 at Physics 9702 Doubts | Help Page 165 - http://physics-ref.blogspot.com/2015/06/physics-9702-doubts-help-page-165.html}
12 – Ans: A. Weight is always
downward. Since the vehicle is at rest, only the weight will have a component
along the slope that will cause the vehicle to go downwards. So, friction, a
force which opposes motion would be in a direction opposite to the component of
the weight along the slope such that the vertical component of friction would
be in a direction opposite to the weight (upward). The normal reaction will be
opposite to the other component of the weight.
13 – Ans: B.
14 – Ans: D. {Detailed explanations for this question is
available as Solution 451 at Physics 9702 Doubts | Help Page 87 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-87.html}
16 - Ans: B. {Detailed explanations for this question is available as Solution 115 at Physics 9702 Doubts | Help Page 21 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-21.html}
17 - Ans: C. {Detailed explanations for this question is available as Solution 183 at Physics 9702 Doubts | Help Page 30 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-30.html}
18 - Ans: A. {Detailed explanations for this question is
available as Solution 131 at Physics 9702 Doubts | Help Page 24 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-24.html}
19 – Ans: C. {Detailed explanations for this question is available as Solution 979 at Physics 9702 Doubts | Help Page 202 - http://physics-ref.blogspot.com/2015/09/physics-9702-doubts-help-page-202.html}
19 – Ans: C. {Detailed explanations for this question is available as Solution 979 at Physics 9702 Doubts | Help Page 202 - http://physics-ref.blogspot.com/2015/09/physics-9702-doubts-help-page-202.html}
20 – Ans: D. {Detailed explanations for this question is available as Solution 1080 at Physics 9702 Doubts | Help Page 228 - http://physics-ref.blogspot.com/2015/12/physics-9702-doubts-help-page-228.html}
23 – Ans: B. {Detailed explanations for this question is
available as Solution 165 at Physics 9702 Doubts | Help Page 28 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-28.html}
24 – Ans: D. Taking wavelength of
violet light to be 4x10-7m gives the frequency to be 7.5x1014Hz
or 1015 when rounded to the nearest power of 10.
25 - Ans: D. {Detailed explanations for this question is available as Solution 179 at Physics 9702 Doubts | Help Page 29 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html}
27 - Ans: C. {Detailed explanations for this question is available as Solution 97 at Physics 9702 Doubts | Help Page 18 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-18.html}
28 - Ans: B. {Detailed explanations for this question is available as Solution 490 at Physics 9702 Doubts | Help Page 95 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-95.html}
29 - Ans: C. {Detailed explanations for this question is available as Solution 840 at Physics 9702 Doubts | Help Page 167 - http://physics-ref.blogspot.com/2015/06/physics-9702-doubts-help-page-167.html}
30 - Ans: D. {Detailed explanations for this question is available as Solution 1124 at Physics 9702 Doubts | Help Page 243 - http://physics-ref.blogspot.com/2016/10/physics-9702-doubts-help-page-243.html}
32 – Ans: C. Resistance of a copper
wire = ρL/A = (1.7x10-8)x2000 / (π(0.5x0.51x10-3)2) = 166Ω. Since wires are parallel (similar to
resistors in parallel), Resistance of cable = (12(1/166))-1 = 14 Ω.
33 - Ans: A. {Detailed explanations for this question is available as Solution 421 at Physics 9702 Doubts | Help Page 79 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-79.html}
35 - Ans: D. {Detailed explanations for this question is available as Solution 423 at Physics 9702 Doubts | Help Page 80 - http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-80.html}
36 - Ans: D. {Detailed explanations for this question is available as Solution 121 at Physics 9702 Doubts | Help Page 22 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-22.html}
38 - Ans: C. {Detailed explanations for this question is available as Solution 181 at Physics 9702 Doubts | Help Page 29 - http://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-29.html}
39 – Ans: B. Roughly the alpha
particle has a mass of 4u, so 4 x 1.66x10-27kg. This gives 6.6x10-27kg
or 10-26 when rounded up.
Explanations have been provided for questions that were found to be more difficult. If you are having other doubts that have not been explained here, you may ask your questions through comments.
Could you do number 27?
ReplyDeletecheck question 97 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-18.html
no. 16 pls?
ReplyDeleteExplanations have been added
DeleteNo .36 please? Thank you! :)
ReplyDeleteExplanations added
DeleteNo 18 please? Thank you ^^
ReplyDeleteadded
DeleteWork solution for June 2013 paper 13 esp Q6, Q19 & Q33
ReplyDeleteTq
Solution for question 19 is available as solution 171 at
Deletehttp://physics-ref.blogspot.com/2014/11/physics-9702-doubts-help-page-28.html
38 please!
ReplyDeleteExplanations for Qu 38 are now available
Deletewhy did you us 33ms to find the mass? thye didmt say its length way 33.
ReplyDeleteWhich question is it? Did you read it correctly because I don't think I would use a value not given in the question
Deletequestion 9
Deletethey didnt say the length is 33m
DeleteIt's the speed of the wind. maybe I missed this detail:
Delete{mass per second = (area x speed) x density = (volume per second) x [mass / volume] = mass per second}
Read the explanations carefully, think and at least try to understand on your own first.
25 please?
ReplyDeleteQ25 has been explained
DeleteThis comment has been removed by the author.
ReplyDeleteI'm currently solving the doubts that were posted before yours. I'll try to solve your questions that you asked soon. But I can't promise that Ill be able to solve them all
DeleteTry to look at the others questions that are already solved in the meantime
DeleteThis comment has been removed by the author.
DeleteSorry, but I can't do that. but i'll try to solve some of the questions you already asked. So, check again
Deletequestion 6 please
ReplyDeleteExplanations for question 6 has been added
DeleteQ33 explanation please?
ReplyDeleteExplanation for this questions has been added
DeleteQ35 please?
ReplyDeleteExplanations for Q35 has been included
Deleteq2
ReplyDeleteAdded
Deleteq28
ReplyDeleteSolution for Q28 is now available
DeleteCan I please get help with these?
ReplyDeletew14/p13/ questions 3 and 27
w14/p12/ questions 10, 21, 23, and 31.
w12/p11/ question 29
some of explained at
Deletehttp://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-102.html
Nov 2014 Paper 13 Q3 explained at
http://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-94.html
Nov 2014 P12 Q10 explained at
Deletehttp://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-103.html
no. 11 please
ReplyDeleteno. 11 please
ReplyDeleteQ11 please
ReplyDeleteQ11 is now explained
DeleteQ5 pls pls please!
ReplyDeleteQ5 included
DeleteCould you add Q29 and Q30 plz?
ReplyDeleteQ29 included
Deletehi can you explain june 2009 paper 1 question 14 and 33 please? :s
ReplyDeleteFor Q14, see solution 843 at
Deletehttp://physics-ref.blogspot.com/2015/06/physics-9702-doubts-help-page-168.html
plz add solution for question 30
ReplyDeleteQ30 explained
Deletefor q13, explanation on C, how will the mass of a body be changing? and if the mass is changing, isn't the momentum should be changing too? since momentum is the product of mass and velocity.
ReplyDeletewe usually do not consider the mass of the fuel but this actually decreases. so the momentum would change and so will the force, even if the speed is constant.
Deletequestion 8 pls?
ReplyDeleteexplanation added
Deletecan you please explain what formula to use in Q9 p12 j2013
ReplyDeletethe explanation has been updated. see again
Deletefor question 20 why did we assume the total pressure the same?
ReplyDeleteWe have not assumed that the pressure is the same.
DeleteWe have compared the pressure in X with the pressure P and the pressure in Y with pressure P since pressure P is the quantity that is present in both equations.