tag:blogger.com,1999:blog-2214461049219354662.post5316589704186713941..comments2024-03-28T13:08:35.581+04:00Comments on Physics Reference: 9702 November 2014 Paper 23 Worked Solutions | A-Level PhysicsUnknownnoreply@blogger.comBlogger17125tag:blogger.com,1999:blog-2214461049219354662.post-22828752749934726172019-02-15T23:42:05.257+04:002019-02-15T23:42:05.257+04:00link addedlink addedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-71177097413681108032019-02-14T19:43:58.492+04:002019-02-14T19:43:58.492+04:0023/O/n/14 question number 7 please23/O/n/14 question number 7 pleaseAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-67616332186559278832018-01-04T13:23:47.895+04:002018-01-04T13:23:47.895+04:00can you solve question no 17 from 2011 m/j paper 1...can you solve question no 17 from 2011 m/j paper 12 please?<br />thanks in advance!! Anonymoushttps://www.blogger.com/profile/12466815238122406637noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-62612252606225852382015-10-20T15:07:44.617+04:002015-10-20T15:07:44.617+04:00I see, I guessed so though but I had doubt that th...I see, I guessed so though but I had doubt that the questions are not related. I am very thankful for your help. =)Anonymoushttps://www.blogger.com/profile/11283659978830050095noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-70247995362229210632015-10-20T10:42:06.244+04:002015-10-20T10:42:06.244+04:00No current flows in cell Y. So, cell Y can be cons...No current flows in cell Y. So, cell Y can be considered to be short circuited and with C at this position, the circuit can be considered to consist of cell X (with internal resistance 1.0 Ω) and the wire BD (having a resistance of 4.0 Ω as calculated in part (a)).<br />Total resistance = 1.0 + 4.0 = 5.0 Ω<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-83057085906346084772015-10-20T06:38:11.723+04:002015-10-20T06:38:11.723+04:00can you explain on qn 6 why resistance is 5?can you explain on qn 6 why resistance is 5?Anonymoushttps://www.blogger.com/profile/11283659978830050095noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-47213784134799031662015-10-17T21:57:27.991+04:002015-10-17T21:57:27.991+04:00Check solution 1019 at
http://physics-ref.blogspot...Check solution 1019 at<br />http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-212.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-60975014065805414452015-10-15T14:49:43.385+04:002015-10-15T14:49:43.385+04:00Check solution 1012 at
http://physics-ref.blogspot...Check solution 1012 at<br />http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-211.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-6505388424312162822015-10-09T17:09:19.330+04:002015-10-09T17:09:19.330+04:00j15p23 Ques 2
please.j15p23 Ques 2<br />please.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-79811877030005007962015-10-09T17:08:15.171+04:002015-10-09T17:08:15.171+04:00j 15 p23 Ques 1 (e)j 15 p23 Ques 1 (e)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-77297604300605868772015-10-08T17:36:03.865+04:002015-10-08T17:36:03.865+04:00Check solution 1000 at
http://physics-ref.blogspot...Check solution 1000 at<br />http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-208.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-26762960197364619672015-10-06T18:51:16.162+04:002015-10-06T18:51:16.162+04:00J15p23 ques 1(e)..
please...
J15p23 ques 1(e)..<br />please...<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-5676749221567534892015-10-06T18:44:54.048+04:002015-10-06T18:44:54.048+04:00j 15 p 23 Ques 5. please...
thank u in advance ......j 15 p 23 Ques 5. please...<br />thank u in advance ...<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-69006384506262555932015-09-10T14:34:58.711+04:002015-09-10T14:34:58.711+04:00Question 4 has been addedQuestion 4 has been addedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-62249240800721899142015-09-09T13:34:16.359+04:002015-09-09T13:34:16.359+04:00Could you help me with question 4 especially the a...Could you help me with question 4 especially the answer for part D?Anonymoushttps://www.blogger.com/profile/11568811844835127948noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-55923965387121267832015-08-03T15:08:07.841+04:002015-08-03T15:08:07.841+04:00Question 3 has now been explainedQuestion 3 has now been explainedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-26003049426463033152015-08-01T18:46:27.579+04:002015-08-01T18:46:27.579+04:00Can you help me with question 3Can you help me with question 3Anonymousnoreply@blogger.com