Physics 9702 Doubts | Help Page 160
Question 793: [Electric
field]
A dipole is a pair of one negative
charge and one positive charge of equal magnitude. Electric field of a dipole
is shown below.
In which direction does the force
act on an electron when at point X?
Reference: Past Exam Paper – June 2012 Paper 11 Q31 & Paper 13 Q31
Solution 793:
Answer: D.
The direction of the electric field
lines indicates the electric force on a positive charge. For an electron, which
has a negative charge, the direction of the force would be in the opposite
direction than that shown by the arrow. [A and B
are incorrect]
At any specific point, the electric
force acts along the tangent to the electric field at a point. At point X, the
direction of the force is along D.
Question 794: [Matter
> Deformation]
Diagram shows the force-extension
graphs for two materials, of the same dimensions, loaded to fracture.
What describes the behaviour of the
materials?
A Both materials are brittle.
B Both materials obey Hooke’s law.
C Both materials are plastic.
D Both materials have the same ultimate
tensile stress.
Reference: Past Exam Paper – November 2012 Paper 12 Q26
Solution 794:
Answer: D.
Both of these wires break at the
same force (or almost). This can be seen by drawing a horizontal line at the maxima
of both curves. This would correspond to the same value of force on the
vertical axis.
The wires have identical diameters
(dimensions) and thus identical cross-sectional areas. So they both have the
same ultimate tensile stress.
Stress = Force / Area
Hooke’s law: F = ke, giving a curve
with a straight line
Choice B is incorrect since one of
the graphs is a curve, and thus does not vary linearly (does not obey Hooke’s
law).
A material is brittle if, when
subjected to stress, it breaks without significant deformation (strain). In a
graph, a brittle material is indicated by the fact that it does not extend
much. That is, the graph would not extend along the horizontal axis. As soon as
a significant force is applied, the material breaks (if it breaks, it can no
longer extend). Only one of the graphs corresponds to this.
Plastic materials undergo permanent deformation,
but does not break easily. The other curve corresponds to this.
Question 795: [Vectors]
What is the component of this
displacement vector in the direction XY?
A 3.0 km B 4.0 km C
5.0 km D 6.6 km
Reference: Past Exam Paper – November 2010 Paper 12 Q3
Solution 795:
Answer: A.
Horizontal component = 5cos(53) =
3.0km
Question 796: [Matter
> Young modulus]
A steel string on an electric guitar
has following properties.
diameter
= 5.0 × 10–4 m
Young
modulus = 2.0 × 1011 Pa
tension
= 20 N
The string snaps, and contracts
elastically.
By what percentage does a length l of
a piece of the string contract?
A 5.1 × 10–4 % B 5.1 × 10–2 % C 1.3 × 10–4 % D 1.3 × 10–2 %
Reference: Past Exam Paper – November 2009 Paper 11 Q 22 & Paper 12 Q21
Solution 796:
Go toA steel string on an electric guitar has the following properties.
Question 797: [Nuclear
Physics]
An isotope of thorium has nucleon
number of 232 and a proton number of 90. It decays to form another isotope of
thorium with nucleon number of 228.
How many alpha particles and beta
particles are emitted by a nucleus of thorium during this decay?
alpha
particles beta particles
A 0
4
B 1
0
C 1
2
D 2
1
Reference: Past Exam Paper – June 2014 Paper 13 Q39
Solution 797:
Answer: C.
Since they are both isotopes of thorium,
the proton number of the isotope formed should also be 90. The total proton number on both sides of the equation should be equal.
Alpha particle is 42α and
beta particle is 0-1β.
Choice A is incorrect since the
proton number of final isotope = 90 – 4(-1) = 94.
For choice B, proton number of final
isotope = 90 – 2 = 88.
Choice C is correct since proton
number of final isotope = 90 – 2 – 2(-1) = 90.
Choice D is incorrect since proton
number of final isotope = 90 – 2(2) – 1(-1) = 87.
Question 798: [Electric
field]
Diagram shows two metal plates
connected to a constant high voltage.
Which graph shows variation of the
electric field strength E midway between the two plates as the distance d
between the two plates is increased?
Reference: Past Exam Paper – November 2014 Paper 11 & 12 Q29
Solution 798:
Answer: A.
Electric field strength, E = V / d
The plates are connected to a power
supply, so the p.d. V across them is constant.
The electric field strength E is
inversely proportional to the distance d between the 2 plates. So, as d
increases, the electric field strength E decreases. [B
and C are incorrect]
A graph of E = V / d at constant
values of V is a curve. This can be done by assigning some values of d.
Question 799: [Matter
> Hooke’s law]
A steel spring has spring constant
of 150 N m–1. When a 25 N weight is hung from the spring, it has a
stretched length of 55 cm.
What was original length of the
spring?
A 0.38 m B 0.49 m C
0.61 m D 0.72 m
Reference: Past Exam Paper – November 2013 Paper 11 & 12 Q24
Solution 799:
Answer: A.
Hooke’s law: F
= kx
That is, the force,
F needed to extend or compress a spring by a distance x is proportional to the distance.
Let the original
length = l.
When F = 25N,
extension x = 0.55 – l
F = k (0.55 - l)
(0.55-l)
= F / k
Original length,
l = 0.55 – (F/k) = 0.55 – (25/150) = 0.38m
In question 796 why diameter is divided by 4 rather than 2?
ReplyDeletearea = pi x r^2
Deleteor area = pi x (d/2)^2 = pi x d^2 / 4
r = d/2
since r is squared, the 2 should also be squared
Ty find very helpfull!!
ReplyDeleteIn question 796 i didnt understand how the equation was re arranged
ReplyDeletethe explanation has been updated
Delete