Question 8
(a) (i) Explain what is meant by a progressive transverse wave. [2]
(ii) Define frequency. [1]
(b) The variation with distance x of displacement y
for a transverse wave is shown in Fig. 7.1.
Fig. 7.1
On Fig. 7.1, five points are
labelled. Use Fig. 7.1 to state any two points having a phase difference of
(i) zero, [1]
(ii) 270°. [1]
(c) The frequency of the wave in (b)
is 15 Hz. Calculate the speed of the wave in (b). [3]
(d) Two waves of the same frequency have amplitudes 1.4 cm
and 2.1 cm.
Calculate the ratio
intensity of wave of amplitude 1.4 cm
intensity of wave of amplitude 2.1 cm
intensity of wave of amplitude 2.1 cm
[2]
Reference: Past Exam Paper – November 2014 Paper 23 Q7
Solution:
(a) (i) A progressive transverse wave is a wave in which energy is
transferred from one place to another (without the bulk movement of the medium)
with the vibration of the particles being at right angles to the direction of
travel of the energy.
(ii) Frequency is defined as the number of oscillations per unit time /
number of wavefronts passing a point per unit time.
(b)
(i)
P and T
{A phase difference of zero means
that the points are in phase. These points are separated by a distance equal to
the wavelength. i.e. two crests, two troughs …}
(ii)
P and S or Q and T
{The difference between point P and
T gives the wavelength (= 1.8 – 0.6 = 1.2 cm). This corresponds to a phase
difference of 360° or zero.
360° - - - > 1.2 cm
1° - - - > 1.2 / 360
270° - - - > 1.2 × 270
/ 360 = 0.9 cm
So, points having a phase difference
of 270° are separated by a distance of 0.9 cm.}
(c)
Wavelength λ = 1.2×10-2 (m)
v = fλ
v = 15 ×1.2×10-2
v = 0.18 m s-1
(d)
{The
intensity is proportional to the square of the amplitude.}
ratio =
(1.4)2 / (2.1)2
ratio = 0.44
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