Question 21
(a)
State what is meant by electric potential at
a point. [2]
(b)
Two parallel metal plates A and B are held a distance d
apart in a vacuum, as illustrated in Fig. 6.1.
Fig. 6.1
Plate A is earthed and
plate B is at a potential of +V0.
Point P is situated in
the centre region between the plates at a distance x
from plate B.
The potential at point
P is V.
On Fig. 6.2, show the
variation with x of the potential V
for values of x from x
= 0 to
x
= d.
Fig. 6.2
[3]
(c)
Two isolated solid metal spheres M and N, each of radius R,
are situated in a vacuum. Their centres are a distance D
apart, as illustrated in Fig. 6.3.
Fig. 6.3
Each sphere has charge
+Q.
Point P lies on the
line joining the centres of the two spheres, and is a distance y
from the centre of sphere M.
On Fig. 6.4, show the
variation with distance y of the electric
potential at point P, for values of y from y
= 0 to y = D.
Fig. 6.4
[4]
[Total: 9]
Reference: Past Exam Paper – June 2019 Paper 42 Q6
Solution:
(a)
The electric potential at a point is the work done in
moving unit positive charge from infinity to the point.
(b)
{The
electric field strength is the negative of the potential gradient.
That is, in
a potential-distance graph, the gradient gives the negative of the field
strength.
Electric
field strength = - potential gradient
The electric
field strength between parallel plates is constant. So, the graph should be a
straight line.
Electric
field strength has a positive value. So, the gradient should be negative so
that the field strength is positive.
Therefore,
the graph is a straight line with negative gradient.
From the
diagram,
When x = 0,
potential = +V0 (0, +V0)
When x = d,
potential = 0 (d, 0)}
(c)
{The
electric potential inside a conductor is constant. That is, from y = 0 to y = R
and from y = D-R to y = D, the potential is constant – it is a horizontal line.
Potential V
= Q / 4πϵ0r
Since both
spheres have the same charge +Q, the magnitudes of the potentials at the surfaces
of the spheres is the same.
The
potential decreases as we move away from one sphere and increases again as we approach
the other sphere. The potential is minimum at the mid-point of the curve as
they have the same charge.
Since the
charges are both positive, the potential is also positive.}
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