Question 14
A sound wave has a
speed of 330 m s-1 and
a frequency of 50 Hz.
What is a possible
distance between two points on the wave that have a phase difference of 60°?
A 0.03 m B 1.1
m C 2.2
m D 6.6
m
Reference: Past Exam Paper – June 2015 Paper 12 Q25
Solution:
Answer: B.
Speed v = 330 m s-1
Frequency f = 50 Hz
Speed v = fλ
Wavelength λ = v / f = 330
/ 50
Wavelength λ = 6.6 m
A distance equal to the
wavelength corresponds to a phase difference of 2π / 360°.
360° - - > 6.6 m
1° - - > 6.6 / 360
60° - - > (6.6/360) ×
60 = 1.1 m
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