Question 26
In the circuit shown, the reading on the ammeter is zero.
The four resistors have different resistances R1, R2, R3 and R4.
Which equation is correct?
A
R1
– R3 = R2 –
R4
B
R1
× R3 = R2 × R4
C
R1
– R4 = R2 –
R3
D R1 × R4 = R2 × R3
Reference: Past Exam Paper – November 2016 Paper 11 & 13 Q36
Solution:
Answer:
D.
For a current to flow in
the ammeter, there should be a potential difference between the terminals of
the ammeter. That is, the potential at one terminal should be different than
the potential at the other terminal.
Since the ammeter reading
is zero, there must be no potential difference across it. That is, the
potential at each terminal of the ammeter is the same – there is no difference.
The potential at the
negative terminal of the cell may be taken to be zero and the potential at the
positive terminal may be taken to be equal to the e.m.f. of the cell.
One approach is to
consider that the potential difference across the resistor with resistance R2
must equal the potential difference across the resistor with resistance R4.
The circuit consists of 2
branches:
Branch 1: R1
and R2
Branch 2: R3
and R4
Both branches form a
potential divider. So, the p.d. across the resistors can easily be obtained by
the potential divider formula.
Let the e.m.f. of the cell
be E.
p.d. across R2
= R2 × E / (R1 + R2)
p.d. across R4
= R4 × E / (R3 + R4)
Since no current flows,
these 2 potentials should be equal.
R2 × E / (R1 + R2) = R4 × E / (R3 + R4)
R2 / (R1
+ R2) = R4 / (R3 + R4)
Rearranging this gives R1R4
= R2R3.
Thank you so much for the such a quick response...Great explanation
ReplyDeleteThank you so much for the solutions...If possible, Could you please post the explanation for May/June 2017 Paper 13 Question 7?
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