Question 7
A car of mass 1400 kg
is travelling on a straight, horizontal road at a constant speed of 25 m s-1.
The output power from the car’s engine is 30 kW.
The car then travels
up a slope at 2° to the horizontal,
maintaining the same constant speed.
What is the output
power of the car’s engine when travelling up the slope?
A 12 kW B 31
kW C 42
kW D 65
kW
Reference: Past Exam Paper – March 2017 Paper 12 Q19
Solution:
Answer:
C.
When the car is travelling
on a horizontal road, its weight is directly downwards and does not contribute
in opposing the motion of the car.
In terms of energy, the engine is only providing
kinetic energy.
Along the slope, a
component of the weight opposes the motion of the car. Thus, the car’s engine
provides both kinetic energy and gravitational potential energy since the car
is gaining in height. In other words, the output power of the car’s engine
should now be greater. [A incorrect]
The KE of the car remains
the same as the car is moving with constant speed. So, this requires the same
amount of power by the car’s engine (= 30 kW).
We need to find out the
extra power required by the car on the slope.
Let the distance moved by
the car along the slope be h.
Gain in height of the car
on the slope is Δh
sin 2
Gain in GPE = mgh sin2
Power = Energy / time = (mgh
sin 2) / t
Power = mgv sin 2 since speed v = h / t
Power = 1400 × 9.8 × 25
sin2 = 12.2 kW
This is the extra power
required by the car on the slope.
Total power of car’s engine
= 30 + 12.2 = 42.2 kW
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