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Tuesday, November 28, 2017

The diagram shows an oscilloscope screen displaying two signals. Signal X has a frequency of 50 Hz and peak voltage of 12 V.




Question 4
The diagram shows an oscilloscope screen displaying two signals.


Signal X has a frequency of 50 Hz and peak voltage of 12 V.

What is the period and peak voltage of signal Y?

period / ms                  peak voltage / V
A                      20                                4
B                      20                                12
C                     50                                4
D                     50                                12





Reference: Past Exam Paper – November 2009 Paper 12 Q3





Solution:
Answer: A.

Vertically, the screen represents the peak voltage (starting from the central horizontal line) and horizontally, it represents the time.

Consider signal X.
3 squares represent 12V
1 square represents (12 / 3 =) 4 V

Frequency = 1 / T = 50 Hz
Period T = 1 / 50 = 0.02 s = 20 ms


Signal Y has the same period as signal X since one complete cycle occupies the same space.
Period of signal Y = 20 ms

The peak voltage of signal Y is represented by 1 square = 1 × 4V = 4 V

1 comment:

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