9702 November 2013 Paper 41 & 42 Worked Solutions | A-Level Physics
Paper 41 and Paper 42 are similar
SECTION A
Question
1
(a)
Gravitational
potential at a point is the work done in moving unit mass from infinity to that
point.
(b)
(i)
gravitational
potential energy = GMm /x
Energy
= (6.67x10-11 x 7.35x1022 x 4.5) / (1.74x106) =
1.27 x 107J
(ii)
Change
in gravitational potential energy = change in
kinetic energy
½
x 4.5 x v2 = 1.27x107
v
= 2.4 x 103ms-1
(c)
As the potential at
Earth’s surface is not zero (less than zero), the Earth would attract the rock. Thus, the
escape speed would be lower.
Question
2
(a)
(i)
N
is the total number of molecule
(ii)
<c2>
is the mean square speed/velocity
(b)
pV
= 1/3 Nm<c2> = NkT
<c2>
= 3kT / m
Mean
kinetic energy = ½ m<c2> = (3/2)kT
(c)
(i)
Either
1
mol contains NA molecules = 6.02x1023 molecules
Energy
required for 1 mol = (3/2)NAkT = (3/2) x 1.38x10-23 x 1.0
x 6.02x1023
=
12.5J
Or
R
= molar gas constant = kNA = 8.31 JK-1mol-1
Energy
= pV = (3/2)RT = (3/2) x 8.31 x 1.0 = 12.5J
(ii)
The
energy required to raise the temperature of the gas by 1K is now greater because
energy is needed to push back (do work against) the atmosphere.
Question
3
(a)
(i)
Choose
any 2 from: 0.3s, 0.9s, 1.5s
(ii)
Either
From
graph,
Maximum
displacement, x = 1.5x10-2m
Period,
T = 1.2s
v
= ωx and ω = 2π/T
v
= (2Ï€/1.2) x 1.5x10-2 = 0.079ms-1
Or
Draw
gradient clearly at either t = 0.3s or t = 1.5s.
Show
the working clearly to give (0.08 ± 0.01)ms-1
(b)
(i)
The
curve should be from (±1.5, 0) passing through (0, 25). The shape should be
similar to the inverted curve for Ep.
Intersections
should occur on both sides between y =12.0 to 13.0mJ.
(ii)
At
maximum amplitude, potential energy is the total energy.
From
graph, total energy = 4.0mJ.
Question
4
{Detailed explanations for this question is available as Solution 574 at Physics 9702 Doubts | Help Page 113 - http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-113.html}
Question
5
(a)
(i)
Field:
right to left
(ii)
Lines
are more spaced out at ends
(b)
The
Hall voltage depends on angle between the field and the plane of the probe. (It is
maximum when the field is normal to the plane or the probe and zero when the
field is parallel to the plane of the probe.)
(c)
(i)
Faraday’s
law of electromagnetic induction states the induced (electromotive force) e.m.f
is proportional to the rate of change of (magnetic) flux (linkage)
(ii)
Choose any
3:
Move
the coil towards/away from solenoid (not considered 2 different ways)
Rotate
the coil
Vary
current in solenoid
Insert
an iron core into the solenoid
Question
6
{Detailed explanations for this question is available as Solution 713 at Physics 9702 Doubts | Help Page 144 - http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-144.html}
Question
7
{Detailed explanations for this question is available as Solution 578 at Physics 9702 Doubts | Help Page 114 - http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-114.html}
Question
8
(a)
Nuclear
binding energy is the energy needed to separate nucleons (in a nucleus) to
infinity.
(b)
(i)
Type
of nuclear reaction: Fission
(ii)
The peak corresponds to atomic mass of Iron which is about 56. You should
refer to the nucleon number for positions.
U
: near right-hand end of line
Mo
: to right of peak, less than 1/3 distance to U
La
: 0.4-0.6 of distance from peak to U
(iii)
1.
Left-hand
side, mass = 236.132u
Right-hand
side, mass = 235.92185u (sum of all on right hand side)
Right-hand
side, mass = 235.922u
Mass
change = 0.210u
2.
Energy
= mc2 = 0.210 x 1.66x10-27 x (3.0x108)2
= 3.1374x10-11J = 196MeV
SECTION B
Question
9
{Detailed explanations for this question is available as Solution 674 at Physics 9702 Doubts | Help Page 135 - http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-135.html}
Question
10
(a)
Main
principles behind the use of ultrasound to obtain diagnostic information about
the internal body structures:
A
quartz / piezo-electric crystal produces a pulse of ultrasound that is reflected from the boundaries between the media
present. The reflected pulse is detected by the ultrasound transmitter and the
signal is processed and displayed. The intensity of the reflected pulse gives
information about the boundary and the time delay gives
information about the depth.
(b)
Advantage
of use of high frequency ultrasound as compared with low frequency ultrasound
for medical diagnosis:
High
frequency ultrasound has a shorter wavelength than low frequency ultrasound, so
smaller structures are resolved/detected.
(c)
(i)
I
= I0exp(-μx)
Ratio
= I/I0 = exp (- 23 x 6.4x10-2) = 0.23
(ii)
An
ultrasound transmitter emits a pulse. When the signal from the pulse is
processed, any signal received later at the detector is usually amplified more
than received at an earlier time because:
The
later signal has passed through a greater thickness of medium and so, has
greater attenuation / greater absorption / smaller intensity
Question
11
(a)
Most
significant bit of sample: underline
left-hand bit
(b)
1010,
1110, 1111, 1010, 1001
(c)
There
are significant changes in detail of changes in V between the times at which
the samplings took place. So, the sampling frequency is inadequate since it is too
low.
Question
12
(a)
Attenuation
of a signal in channels of communication is usually measured on a logarithmic
rather than a linear scale because the gain of amplifiers is a series found by
addition (not multiplication). The logarithmic scale provides a smaller number.
(b)
For
a particular channel of communication having low attenuation, input power =
6.5mW and the attenuation per unit length = 1.8dBkm-1
(i)
Name
of channel of communication: Optic fibre
(ii)
Distance
over which the power of the signal is reduced to 1.5x10-15W:
P2
: input power P1 :
output power
Attenuation/dB
= 10lg(P2/P1) = 10lg({6.5x10-3}/{1.5x10-15})
= 126
Length
= 126/1.8 = 70km
can you please do w13 qp 43
ReplyDeletequestion number 1c?
the question is explained at
Deletehttp://physics-ref.blogspot.com/2015/03/physics-9702-doubts-help-page-86.html
Salam
ReplyDeletePlz explain question 4 c) ii) 2 ...
Wslm.
DeleteThe details have been updated. Check again
Asalamualaikum Sir,
ReplyDeleteCould you please further explain how you've derived the eqns. (in the step: "Either E = p2/2m or p = (2Em)½") in question 7 part (c)?
The derivations have been added, though this equation may be used directly.
Deletecan you please draw 9bii) in w13 qp 43?
ReplyDeleteSee solution 664 at
Deletehttp://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-133.html
Thank you. can you please also do w13 qp 42 9b ?
DeleteMore details have been added for question 9
DeleteHI, could you please show how to sketch Q6(c)(ii)? Or some diagrams similar to it? Thanks!
ReplyDeleteThe details have been updated
Deletehello,can you please explain why we multiply by 2 and square in 4 aii) w13 qp 42?
ReplyDeleteI have added a few lines at the solution for the question. See if it helps.
DeleteCould you please show me an example of the sketch for Q6(c)(ii) ? Thanks.
ReplyDeleteSketch included
Delete