Question 7
(a)
A particle has mass m, charge +q
and speed v.
State the magnitude
and direction of the force, if any, on the particle when the particle is
travelling along the
direction of
(i)
a uniform gravitational field of field strength g,
[2]
(ii)
a uniform magnetic field of flux density B.
[1]
(b)
Two charged horizontal metal plates, situated in a vacuum, produce a
uniform electric field of field strength E between
the plates. The field strength outside the region between the plates is zero.
The particle in (a)
enters the region of the electric field at right-angles to the
direction of the field, as illustrated in Fig. 6.1.
Fig. 6.1
A uniform magnetic
field is to be applied in the same region as the electric field so that the
particle passes undeviated through the region between the plates.
(i)
State and explain the direction of the magnetic field. [2]
(ii)
Derive, with explanation, the relation between the speed v
and the magnitudes of the
electric field
strength E and the magnetic flux
density B. [3]
(c)
A second particle has the same mass m
and charge +q as that in (b)
but its speed is 2v. This particle enters
the region between the plates along the same direction as the particle in (b).
On Fig. 6.1, sketch
the path of this particle in the region between the plates. [2]
Reference: Past Exam Paper – November 2015 Paper 41 & 42 Q6
Solution:
(a)
(i)
force = mg
along the
direction of the field/of the motion
{The
gravitational force on the particle in downwards, along the direction of the
field (which is also downwards).}
(ii)
no force
{The
particle will only feel an electromagnetic force when the direction of motion
is perpendicular (or has a component perpendicular) to the direction of the
magnetic field.}
(b)
(i)
force due
to E-field downwards so force due to B-field upwards
into the
plane of the paper
{The direction
of the electric field strength E indicates the direction of the electric force
on a positive charge. So, the electric field would cause a downward force on
the particle.
For the
particle to pass undeviated, the force exerted by the magnetic field should be
upwards.
From Fleming’s
left hand rule,
Thumb =
force = up
Middle
finger = current = to the right
So,
forefinger = (magnetic) field = into plane of paper}
(ii)
force due
to magnetic field = Bqv
force due
to electric field = Eq
the forces
are equal (and opposite)
{Bqv = Eq
Bv = E}
so Bv = E or Eq
= Bqv so E = Bv
(c)
sketch: smooth curved path in ‘upward’ direction
{Remember
that the magnetic force is upwards while the electric force is downwards.
The speed
v only affects the magnetic force (= Bqv) and NOT the electric force (= Eq;
does not depend on v).
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