Question 4
(a)
During melting, a solid becomes liquid with little or no change in
volume.
Use kinetic theory to
explain why, during the melting process, thermal energy is required
although there is no
change in temperature. [3]
(b)
An aluminium can of mass 160 g contains a mass of 330 g of warm
water at a temperature of 38 °C, as illustrated in Fig. 3.1.
Fig. 3.1
A mass of 48 g of ice
at –18 °C is taken from a freezer and put in to the water. The ice melts and
the final temperature of the can and its contents is 23 °C.
Data for the specific
heat capacity c of aluminium, ice and
water are given in Fig. 3.2.
c / J g-1 K-1
aluminium 0.910
ice 2.10
water 4.18
Fig.
3.2
Assuming no exchange
of thermal energy with the surroundings,
(i)
show that the loss in thermal energy of the can and the warm water
is 2.3 × 104 J, [2]
(ii)
use the information in (i) to calculate a value L
for the specific latent heat of fusion of ice. [2]
[Total: 7]
Reference: Past Exam Paper – June 2018 Paper 42 Q3
Solution:
(a)
(During melting,)
the bonds between atoms/molecules are broken, so the potential energy of
atoms/molecules is increased.
{Since the volume of the substance does not
change – work done = pΔV =
0}
No/little work is done, so the required input
of energy is thermal energy.
{The input
of energy cannot be through work being done on the system.}
(b)
(i)
{Heat loss occurs both in the aluminium can and
the warm water.
Heat loss of can = 160 × 0.910 × (38-23)
Heat loss of water = 330 × 4.18 × (38-23)}
(ΔQ =) mcΔθ
loss = (160 × 0.910 × 15)
+ (330 × 4.18 × 15)
loss = 2.3 × 104 J
(ii)
{The heat loss by the can and warm water is
gained by the ice to:
(1) increase its temperature (of ice) from -18°C to 0°C [Q = 48 × 2.10 × (0- -18)]
(2) change its state from solid to liquid
(melting) [Q = mL = 48
L]
(3) raise temperature of liquid from 0°C to 23°C [Q = 48 × 4.18 × (23-0)]}
2.3 × 104 = (48 × 2.10 × 18)
+ 48L + (48 × 4.18 × 23)
48L = 1.66 × 104
Specific
latent heat of fusion, L = 350 J g-1
In raise in temperature of liquid why didn’t we subtract 23 from 38? Can you explain?
ReplyDeletewhich part are you referring to? it is done in (b)(i)
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