Question 14
In a large container
in an oil refinery, three oils of different densities are mixed. No chemical activity
occurs.
The mixture consists
of
1200
kg of oil of density 1100 kg m-3,
1500
kg of oil of density 860 kg m-3,
4000
kg of oil of density 910 kg m-3.
What is the density of
the mixture?
A 927 kg m-3 B 957
kg m-3 C 1010
kg m-3 D 1080
kg m-3
Reference: Past Exam Paper – June 2016 Paper 12 Q13
Solution:
Answer:
A.
Density of mixture = total
mass / total volume
Density = mass / volume
Volume = mass / density
Volume of the 1200 kg oil
= 1200 / 1100 = 1.091 m-3
Volume of the 1500 kg oil
= 1500 / 860 = 1.744 m-3
Volume of the 4000 kg oil
= 4000 / 910 = 4.396 m-3
Total mass = 1200 + 1500 +
4000 = 6700 kg
Total volume = 1.091 +
1.744 + 4.396 = 7.231 m-3
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