Question 15
The diagram shows the waveform of a signal displayed on a
cathode-ray oscilloscope.
The time-base is set at 5.0 ms per division.
The Y-gain is set at 5.0 mV per division.
What are the amplitude and the frequency of the signal?
amplitude / mV frequency / Hz
A
10 50
B
10 100
C
20 50
D 20 100
Reference: Past Exam Paper – November 2018 Paper 11 Q23
Solution:
Answer:
A.
The amplitude is measured (vertically)
starting from the central line to the peak.
Y-gain = 5.0 mV per div
Amplitude = 2 div = 2 × 5.0 = 10 mV
The period is measured horizontally.
One complete wave occupies 4 div.
Time-base setting = 5.0 ms
per div
Period T = 4 div = 4 × 5.0 = 20 ms =
20×10-3 s
Frequency = 1 / T = 1 / (20×10-3) = 50 Hz
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