Question 19
A wire has a final length of 6.0 m after undergoing a strain of 200%.
What is the original length of the wire?
A 1.5 m B 2.0 m C 3.0 m D 4.0 m
Reference: Past Exam Paper – November 2015 Paper 11 Q23
Solution:
Answer: B.
Let the original length = L
Extension = 6 – L
Percentage strain = (extension / Original length) × 100%
200 % = ((6 – L) / L) × 100%
(6 – L) / L = 200/100
(6 – L) / L = 2
6 – L = 2L
6 = 2L + L
L = 6/3 = 2 m
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