Question 2
A student investigates
the energy changes of a mass oscillating on a vertical spring, as shown in Fig.
4.1.
Fig. 4.1
The student draws a
graph of the variation with displacement x of
energy E of the oscillation, as
shown in Fig. 4.2.
Fig. 4.2
(a)
State whether the energy E represents the total
energy, the potential energy or the kinetic energy of the oscillations. [1]
(b)
The student repeats the investigation but with a smaller amplitude.
The maximum value of E is now found to be 1.8
mJ.
Use Fig. 4.2 to
determine the change in the amplitude. Explain your working. [3]
Reference: Past Exam Paper – June 2014 Paper 41 & 43 Q4
Solution:
(a)
Kinetic energy / KE / EK
{At
the maximum displacement, the energy is entirely gravitational potential. The
mas is momentarily at rest and thus, its kinetic energy is zero.}
(b)
{Initially, the maximum
energy was 2.4 mJ and now, it is 1.8 mJ.
So, change in maximum
energy = 2.4 – 1.8 = 0.6 mJ}
EITHER Change in energy =
0.60 mJ
OR The maximum
value of E is proportional to (amplitude)2 / equivalent numerical
working
{The maximum value of (kinetic
energy) E from the graph is the same as the total energy.
Total energy Etotal =
½ mω2x02
The total energy is
proportional to the square of the amplitude.
Method
1 (based on calculation):
From the graph,
2.4 mJ corresponds to an amplitude
of 1.5 cm.
Since Etotal ∝ x02,
2.4 ∝ 1.52 ------------------ (1)
For 1.8 mJ, let the new amplitude
be a.
1.8 ∝ a2 -----------------
(2)
Take (2) divide by (1),
2.4 / 1.8 = 1.52
/ a2
giving
a2 = (1.8/2.4) ×
1.52
a = 1.3 cm}
The new amplitude is 1.3 cm
Change in amplitude (= 1.5
– 1.3) = 0.2 cm
{OR Method 2 (more
direct – based on graph): - this was the expected method to use
Change in energy = 0.60 mJ
We can use this fact to
find the change in amplitude that corresponds to the change in energy found
above from the graph directly.
We can look in the graph
for the amplitude that corresponds to an energy of 0.6 mJ.
From the graph, when the
energy changes by an amount of 0.6 mJ, the corresponding max amplitude (for 0.6
mJ) is 1.3 cm.
Initial max amplitude = 1.5
cm
New max amplitude = 1.3 cm
Change in amplitude = 1.5 – 1.3 = 0.2 cm}
please tell why we look the value of x that corresponds to o.6..why not 1.8...?
ReplyDeletewe want the value of x for the CHANGE in max energy, but the max energy itself
DeleteCan you please explain your answer
ReplyDeletewhich part and what to explain exactly?
Delete