Question 7
A molecule behaves as
an electric dipole consisting of two equal point charges, of opposite sign, separated
by a fixed distance. The molecule moves with constant horizontal velocity as it
enters a vertical uniform electric field, as shown.
The positive and
negative charges of the molecule enter the field at the same time.
Which row describes the velocity of the
molecule in the field?
Reference: Past Exam Paper – June 201 Paper 13 Q30
Solution:
Answer:
B.
Initially, before entering
the electric field, the velocity of the molecule is horizontal. That is, it has
no vertical component of velocity (= 0).
The electric field is
vertically downwards. This would produce a vertical force on a charge.
Electric field lines are
drawn from positive to negative. So, the positive charge of the molecule is
attracted downwards while the negative charge is attracted upwards in the
field.
But since the charges are
separated by a fixed distance, the forces on the charges of the molecule cancel
out.
Thus, the vertical
velocity of the molecule (initially zero) does not experience any resultant
force. The vertical velocity remains the same (it remains zero).
The electric field is vertical. So, it does not have any effect on the horizontal component of velocity. The horizontal component of velocity remains constant.
Answer is D in the marking scheme
ReplyDeletei checked again and the answer is B
DeleteWhat about the weight of the molecule?
ReplyDeleteno information has been given about the mass or a gravitational field.
Deleteso, we ignore the weight