9702 November 2014 Paper 22 Worked Solutions | A-Level Physics
Paper 22
Question 1
{Detailed explanations for this question is available as Solution 688 at Physics 9702 Doubts | Help Page 139 - http://physics-ref.blogspot.com/2015/05/physics-9702-doubts-help-page-139.html}
Question 2
{Detailed explanations for this question is available as Solution 527 at Physics 9702 Doubts | Help Page 102 - http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-102.html}
Question 3
{Detailed explanations for this question is available as Solution 1030 at Physics 9702 Doubts | Help Page 215 - http://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-215.html}
Question 5
{Detailed explanations for this question is available as Solution 1123 at Physics 9702 Doubts | Help Page 242 - http://physics-ref.blogspot.com/2016/09/physics-9702-doubts-help-page-242.html}
Question 6
{Detailed explanations for this question is available as Solution 1082 at Physics 9702 Doubts | Help Page 229 - http://physics-ref.blogspot.com/2015/12/physics-9702-doubts-help-page-229.html}
Question 7
In the decay of a nucleus of 21084 Po, an α-particle is emitted with energy 5.3 MeV.
Explanations have been provided for questions that were found to be more difficult. If you are having other doubts that have not been explained here, you may ask your questions through comments.
j15 p22 Ques 2
ReplyDeleteCheck solution 1023 at
Deletehttp://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-213.html
j 15 p22 Ques 3
ReplyDeleteplease..
thank u in advance
See solution 1018 at
Deletehttp://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-212.html
j 15 p 22 Ques 5
ReplyDeleteSee solution 1004 at
Deletehttp://physics-ref.blogspot.com/2015/10/physics-9702-doubts-help-page-209.html
w14_qp_22_q-3
ReplyDeleteAdded
DeleteNov 2014 p22 question 6
ReplyDeleteQuestion 6 has been added
DeleteNov 2013 p21 question 5
ReplyDeleteGo to
Deletehttp://physics-ref.blogspot.com/2014/06/9702-november-2013-paper-21-22-worked.html
Nov 2014 qp22 ex5
ReplyDeleteExplanations added
DeleteQuestion no.7 of october/november 2014 paper22
ReplyDeleteQ7 solved and added
Deletehow is average velocity calculated in question 2 to calculate kE
ReplyDeleteVh = 5.9 tan 30°
Deleteand Vh = V cos 60°.
So, V = (Vh / cos 60 =) 5.9 tan 30° / cos 60° = 6.81 ms-1.