Saturday, November 24, 2018

A student is using a power supply that produces a sinusoidal output. The meters on the supply show that the output voltage V has a root-mean-square (r.m.s.) value of 14 V with a frequency of 750 Hz.


Question 1
A student is using a power supply that produces a sinusoidal output. The meters on the supply show that the output voltage V has a root-mean-square (r.m.s.) value of 14 V with a frequency of 750 Hz.

The variation with time t of the output voltage V may be represented by the expression
V = V0 sin ωt.

(a) Determine the value of
(i) V0, [1]
(ii) ω. [1]


(b) A capacitor with a large capacitance is connected across the terminals of the supply.
Suggest and explain why this may lead to a large current from the supply. [3]





Reference: Past Exam Paper – November 2015 paper 43 Q7





Solution:
(a)
(i)
{Vrms = V0 / 2
V0 = Vrms × √2}
V0 (= 14 2 ) = 19.8 (20) V

(ii)
{ω = 2πf}
ω (= 2π × 750) = 4700 rad s–1


(b)
{Capacitance C = Q / V
Since the capacitance is large, the amount of charge Q required will also be large.}
A large amount of charge is required to charge the capacitor {of large capacitance}.

{The output of the supply is sinusoidal, so the capacitor would charge and discharge very rapidly (depending on the frequency). The high frequency gives rise to a very short charging/discharging time.}
The capacitor would charge and discharge rapidly.

{I = Q / t,} As current is the charge per unit time, the large charge would produce a large current.

4 comments:

  1. Can you please explain in more detail how exactly does a large frequency give rise to short discharging/charging time? Thanks a lot!

    ReplyDelete
    Replies
    1. e.g. frequency = 750 Hz

      This means that in 1 second, the capacitor charges and discharges 750 times. So, the time for 1 charging/discharging should be very small in order for this process to occurs 750 times in 1 second.

      Delete
  2. In this question is the capacitor connected across (in parallel) to the supply (battery) or the output (say resistor)? A bit confused

    ReplyDelete

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