tag:blogger.com,1999:blog-2214461049219354662.post7574671291253764977..comments2024-03-28T13:08:35.581+04:00Comments on Physics Reference: 9702 June 2014 Paper 41 43 Worked Solutions | A-Level PhysicsUnknownnoreply@blogger.comBlogger20125tag:blogger.com,1999:blog-2214461049219354662.post-52277044345188786262019-02-13T23:03:23.139+04:002019-02-13T23:03:23.139+04:00explanation has been updatedexplanation has been updatedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-14371791199666138752019-02-13T17:11:37.492+04:002019-02-13T17:11:37.492+04:00Kindly explain why we can't use the formulas, ...Kindly explain why we can't use the formulas, E=0.5Q^2/C, E=0.5CV^2 OR E=0.5QV, for the Q.6 (a.1) in MJ14-41?? Thanks alooottsaadia zia ulhaquehttps://www.blogger.com/profile/14095909835126113878noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-60794462876204153852017-11-11T21:49:51.123+04:002017-11-11T21:49:51.123+04:00follow the instructions given above. The graph wil...follow the instructions given above. The graph will take that form.<br /><br />It's important that you understand what is happening (from the explanation) instead of having the final answer directly.<br /><br />THnxAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-13988265722227508882017-11-11T19:23:48.855+04:002017-11-11T19:23:48.855+04:00Where are the graphs for question 5
May June 2014 ...Where are the graphs for question 5<br />May June 2014 41Rjrididiehttps://www.blogger.com/profile/02415803318196998722noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-4359754077353084672015-10-13T14:19:36.165+04:002015-10-13T14:19:36.165+04:00Q7 has been explainedQ7 has been explainedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-65662403886741880432015-10-13T03:54:29.894+04:002015-10-13T03:54:29.894+04:00Hye can you explain question 7 June 2014Hye can you explain question 7 June 2014Anonymoushttps://www.blogger.com/profile/08306137571565091251noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-81651083954654249632015-04-28T17:17:06.051+04:002015-04-28T17:17:06.051+04:00For question 4, check solution 632 at
http://physi...For question 4, check solution 632 at<br />http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-125.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-21426246895521345342015-04-26T15:00:09.908+04:002015-04-26T15:00:09.908+04:00Check question 624 at
http://physics-ref.blogspot....Check question 624 at<br />http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-123.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-16811036132195317222015-04-26T11:05:32.809+04:002015-04-26T11:05:32.809+04:00Even though this not directly shown in the graph, ...Even though this not directly shown in the graph, it is known that the electric potential starts to decrease from the surface of the sphere from further away and that the electric potential is constant inside the sphere. Since the graph starts at x = 1cm (and the part before x = 1cm is not shown [it is not be zero]), we can infer that before x = 1cm, we are inside the sphere.<br /><br />If the radius was greater than 1.0cm, the electric potential should be constant for some values of x after x = 1cm.<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-28657881733462949162015-04-25T23:45:42.971+04:002015-04-25T23:45:42.971+04:00for Nov 2014 P41 Q5 b i, how is electric potential...for Nov 2014 P41 Q5 b i, how is electric potential constant? as you go to the right,the potential decreases. Moreover, even if the potential is constant. why would that prevent the radius from being any bigger?Anonymoushttps://www.blogger.com/profile/09194252062835703681noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-84566186096636806722015-04-25T22:10:19.617+04:002015-04-25T22:10:19.617+04:00For Nov 2014 P41 Q5, see question 619 at
http://ph...For Nov 2014 P41 Q5, see question 619 at<br />http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-122.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-11442766612295006262015-04-24T15:10:51.817+04:002015-04-24T15:10:51.817+04:00For the first one, see solution 615 at
http://phys...For the first one, see solution 615 at<br />http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-121.html<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-51304435011742678002015-04-24T14:59:50.779+04:002015-04-24T14:59:50.779+04:00Details have been updatedDetails have been updatedAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-25725770419878524492015-04-24T03:54:00.233+04:002015-04-24T03:54:00.233+04:00Can you explain to me the answer for 14c) in detai...Can you explain to me the answer for 14c) in detail?<br />Do you mind explaining to me answer for O/N 2014/41 question 5b)ii) as well? <br />Your help is much appreciated :) Anonymoushttps://www.blogger.com/profile/17323051015707435600noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-34585107808104221772015-04-24T03:49:28.157+04:002015-04-24T03:49:28.157+04:00Can you explain to me the answers in 14)c) in deta...Can you explain to me the answers in 14)c) in detail? Thanks :) Anonymoushttps://www.blogger.com/profile/17323051015707435600noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-59925252557957403032015-04-23T11:45:17.358+04:002015-04-23T11:45:17.358+04:00Firstly, I would like to point out that if you rea...Firstly, I would like to point out that if you read the application booklet carefully, these are already explained well.<br /><br />But for a quick explanation:<br />What saturation means?<br />The supply line usually provide a potential of about 9.0V, 6.0V, ... (like these values) to the op-amp. If there is a significant difference between the input potentials (inverting and non-inverting or V- and V+ here), the output voltage would be very much larger than the voltages supplied by the supply line. (see application booklet for examples)<br /><br />From the conservation of energy, this is not possible - a supply voltage of 9.0V cannot give an output voltage of, say, 10 000V. SO, then the output would be equal to the supply voltage, 9.0V here. THat is what we call saturation. Theoretically, the output should be 10 000V, but in reality this is not the case. We say that the op-amp has been saturated.<br /><br /><br />Infinite gain is that very large value of output obtained theoretically, when compared to the input potential.<br /><br /><br /><br />However, saturation does not occur if the inputs are approximately the same. V+ is connected to the ground, so its potential is 0.0V. For the op-amp not to saturate, V- should be approximately equal to V+. Since V+ is zero, V- should be approximately equal to zero. That's why it's called virtual earthAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-31465111621718378102015-04-22T19:23:45.277+04:002015-04-22T19:23:45.277+04:0011 ciii) why is it multiplied instead of dividing?...11 ciii) why is it multiplied instead of dividing?and 12 c it says greater number of voltage and then smaller voltage which doesnt make sense for w 14 qp 43. Thank you very much.Anonymoushttps://www.blogger.com/profile/09194252062835703681noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-91992645407931349912015-04-22T19:02:37.651+04:002015-04-22T19:02:37.651+04:00in 10 b i) can you explain"op-amp has very la...<br />in 10 b i) can you explain"op-amp has very large / infinite gain and so saturates" this statement?whats saturation and infinite gain ?Anonymoushttps://www.blogger.com/profile/09194252062835703681noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-80120698705049877552015-04-22T17:32:14.742+04:002015-04-22T17:32:14.742+04:00and 4 c for the same paper.and 4 c for the same paper.Anonymoushttps://www.blogger.com/profile/09194252062835703681noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-51384641791397172262015-04-22T16:45:21.654+04:002015-04-22T16:45:21.654+04:00can you please graph 2c from w14 qp 43?
2b (same p...can you please graph 2c from w14 qp 43?<br />2b (same paper) is it a straight line passing through origin because f=bqv where v is proportional to f?Anonymoushttps://www.blogger.com/profile/09194252062835703681noreply@blogger.com