tag:blogger.com,1999:blog-2214461049219354662.post5380739902190764210..comments2024-03-28T13:08:35.581+04:00Comments on Physics Reference: Physics 9702 Doubts | Help Page 138Unknownnoreply@blogger.comBlogger33125tag:blogger.com,1999:blog-2214461049219354662.post-28366253648822990222018-09-11T22:34:02.375+04:002018-09-11T22:34:02.375+04:00The e.m.f. in a circuit is equal to the sum of p.d...The e.m.f. in a circuit is equal to the sum of p.d. in the circuit.<br /><br />Consider the middle loop. From Ohm’s law, V = IR giving 12 = I2 x 10 where resistance of wire = 10Ω.<br />I2 = 12 / 10 = 1.2 A<br /> <br />Consider the lower loop. From Ohm’s law, V = IR giving 12 = I3 x (4+2)<br />I3 = 12 / 6 = 2 A<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-80056005176184634872018-09-11T03:18:59.331+04:002018-09-11T03:18:59.331+04:00HEY PLEASE PLEASE PLEASE PLEASE HELP ME QUESTION 6...HEY PLEASE PLEASE PLEASE PLEASE HELP ME QUESTION 685 a part three please kindly tell me how the I2 and I3 must be found please! Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-12743027685000814692018-04-18T21:28:55.379+04:002018-04-18T21:28:55.379+04:00the motion is usually considered to be horizontal....the motion is usually considered to be horizontal. the weight, which is vertically down, does not affect the motionAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-23478436742502333642018-04-18T19:47:16.072+04:002018-04-18T19:47:16.072+04:00In solution 684,F is the resultant force but we ha...In solution 684,F is the resultant force but we have to calculate frictional force ! So why we haven't calculated mg-friction force=maAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-65199807575554109472016-10-05T17:17:37.221+04:002016-10-05T17:17:37.221+04:00Stage 1 is constant velocity of 18m/s. That is, it...Stage 1 is constant velocity of 18m/s. That is, it continues to travel at this speed.<br /><br />Stage 2 is constant deceleration. that is, the speed is decrease by equal amount in equal interval of time.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-9585235535092175652016-10-05T17:12:36.571+04:002016-10-05T17:12:36.571+04:00Resultant force F = ma. Deceleration or Accelerati...Resultant force F = ma. Deceleration or Acceleration = gradient of stage 2 on graph. Consider points (3.5, 0) and (0.65, 18). Acceleration = (18 – 0) / (0.65 – 3.5) = - 6.3 ms-2. Deceleration = 6.3 ms-2.<br /><br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-40176734234667696682016-10-04T07:06:51.762+04:002016-10-04T07:06:51.762+04:00Also, constant speed is it constant magnitude as i...Also, constant speed is it constant magnitude as in 40m/s horizontal line in a graph or constant as in constant increase that happens when acceleration is >0 but constant? Then what about accelerating? Does it mean accelerate uniformly or what?Anonymoushttps://www.blogger.com/profile/04225108841291904994noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-19625301386499471972016-10-04T06:06:44.701+04:002016-10-04T06:06:44.701+04:00I'm sorry, but I don't understant 684 bii ...I'm sorry, but I don't understant 684 bii about the resistive force at all. Could you elaborate?Anonymoushttps://www.blogger.com/profile/04225108841291904994noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-85297956425868107042016-04-10T21:39:53.932+04:002016-04-10T21:39:53.932+04:00See solution 1106 at
http://physics-ref.blogspot.c...See solution 1106 at<br />http://physics-ref.blogspot.com/2016/04/physics-9702-doubts-help-page-237.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-5527781422516885622016-04-08T18:29:27.187+04:002016-04-08T18:29:27.187+04:00Could you solve (Oct/Nov 2015 Variant 22 Q6) pleas...Could you solve (Oct/Nov 2015 Variant 22 Q6) please? I dont know why I feel like all the concepts are so different.. Amnahttps://www.blogger.com/profile/08061146174437208489noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-68516210493750360582015-12-30T10:30:22.694+04:002015-12-30T10:30:22.694+04:00Upon collision, the hard ball is momentarily at re...Upon collision, the hard ball is momentarily at rest (EK = 0). But from the law of conservation of energy, its previous KE cannot be destroyed, it should have been converted into another form of energy. The hard ball does not deform, so the KE does not become strain energy of the hard ball. In fact, its KE has been converted into strain energy of the glass. Since strain energy is associated with deformation, as all of the KE of the hard ball have completed been converted into strain energy of the glass, the glass is more likely to deform, that is, break.<br /><br />As for the soft ball, as it collides with the glass it compresses. Thus some of the KE of the soft ball is converted into strain energy of the soft ball. The remaining amount of energy is converted into strain energy of the glass. Hence, comparing the hard and soft balls, more energy has been converted into strain energy of the glass for the collision of the hard ball. So, the glass is more likely to break with the hard ball.<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-65322260721896675392015-12-30T01:16:20.889+04:002015-12-30T01:16:20.889+04:00please replyplease replyAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-12433049689750790512015-12-29T22:22:35.895+04:002015-12-29T22:22:35.895+04:00but it is mentioned that hard ball doesn't und...but it is mentioned that hard ball doesn't undergo deformationAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-16478599089931728692015-12-29T21:59:38.067+04:002015-12-29T21:59:38.067+04:00Strain energy is the energy stored in an object un...Strain energy is the energy stored in an object undergoing deformation – here compression.<br /><br />now, go through the explanations at<br />http://physics-ref.blogspot.com/2015/01/physics-9702-doubts-help-page-48.html<br /><br />againAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-16311945429424584552015-12-29T20:03:36.021+04:002015-12-29T20:03:36.021+04:00can u please explaincan u please explainAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-84741680441573135592015-12-29T14:19:53.171+04:002015-12-29T14:19:53.171+04:00See solution 1085 at
http://physics-ref.blogspot.c...See solution 1085 at<br />http://physics-ref.blogspot.com/2015/12/physics-9702-doubts-help-page-230.htmlAdminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-36591644250416054472015-12-29T12:44:41.884+04:002015-12-29T12:44:41.884+04:00for the hard ball I dont understand how is all kin...for the hard ball I dont understand how is all kinetic energy converted to strain energyAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-71907591438115894272015-12-29T10:25:06.139+04:002015-12-29T10:25:06.139+04:00Let me know exactly what you are not understanding...Let me know exactly what you are not understanding at the post with solution 288. It would be easier to explain then.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-20013332589688603762015-12-28T23:06:52.966+04:002015-12-28T23:06:52.966+04:00I know that solution 288 is there for than questio...I know that solution 288 is there for than question but I still don't understand so it will be better if u explain in more detail. thanksAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-91775734941904216732015-12-28T23:02:25.935+04:002015-12-28T23:02:25.935+04:00paper 2paper 2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-68490184841954352792015-12-28T23:01:58.693+04:002015-12-28T23:01:58.693+04:00paper 2paper 2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-66408555350968647532015-12-28T17:34:04.589+04:002015-12-28T17:34:04.589+04:00which paper?which paper?Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-20172808918379042242015-12-28T17:19:30.917+04:002015-12-28T17:19:30.917+04:00can you please explain 9702 may june 2005 q4 (c)can you please explain 9702 may june 2005 q4 (c)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-12574695786446689302015-12-28T17:18:15.903+04:002015-12-28T17:18:15.903+04:00can you please give explanation of 9702 may june 2...can you please give explanation of 9702 may june 2005 q2 Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-17969755981366726352015-08-15T15:01:24.451+04:002015-08-15T15:01:24.451+04:00Explanations have been added at the end of the que...Explanations have been added at the end of the question.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.com