tag:blogger.com,1999:blog-2214461049219354662.post5016998894393013864..comments2024-03-28T13:08:35.581+04:00Comments on Physics Reference: Physics 9702 Doubts | Help Page 79Unknownnoreply@blogger.comBlogger7125tag:blogger.com,1999:blog-2214461049219354662.post-26449769646194360912019-01-03T11:21:40.987+04:002019-01-03T11:21:40.987+04:00we can use the equation whenever we have 2 resisto...we can use the equation whenever we have 2 resistors in series.<br /><br />Here, (the internal resistance of) the supply is in series with the heater.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-91253405752385085342019-01-01T20:57:08.216+04:002019-01-01T20:57:08.216+04:00for question 421, how do we know to use the potent...for question 421, how do we know to use the potential divider equation? it does not mention in the question that it is a potential dividerAnonymoushttps://www.blogger.com/profile/09553642993175361068noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-60565885428288051662018-03-17T22:15:18.955+04:002018-03-17T22:15:18.955+04:00yes, but you will need to do more calculations to ...yes, but you will need to do more calculations to find the resistance.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-37127636080699353652018-03-17T02:32:33.267+04:002018-03-17T02:32:33.267+04:00for qs 418, can I use P=VI instead of P= I^2R?for qs 418, can I use P=VI instead of P= I^2R?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-36498436186434957762015-10-23T05:31:56.681+04:002015-10-23T05:31:56.681+04:00Okay I understand now :) Thank you!Okay I understand now :) Thank you!Mun Yennoreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-89637851962515034442015-10-22T20:46:06.854+04:002015-10-22T20:46:06.854+04:00The power supplied to the water is the power from ...The power supplied to the water is the power from the heater. Thus, the quantities involved in the equation are for the heater – that is, p.d. across heater, current through heater and resistance of heater.Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-70239870109257640532015-10-22T20:23:22.862+04:002015-10-22T20:23:22.862+04:00May I know how do we know which resistance to sub ...May I know how do we know which resistance to sub in the equation for question 421?<br />Thanks in advance! xxMun Yennoreply@blogger.com