tag:blogger.com,1999:blog-2214461049219354662.post210280090761955446..comments2024-03-19T12:06:52.198+04:00Comments on Physics Reference: Physics 9702 Doubts | Help Page 82Unknownnoreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2214461049219354662.post-57919466999406636372015-11-04T17:15:15.133+04:002015-11-04T17:15:15.133+04:00Wslm.
The sum of p.d.`s in the middle loop is 2.0V...Wslm.<br />The sum of p.d.`s in the middle loop is 2.0V.<br />Potential divider equation: V1 = [R1 / (R1+R2)] × E<br />(p.d. across P and S,) V1 = [5 / (5+5)] × 2 = 1.0 V<br />Adminhttps://www.blogger.com/profile/03708185681043991662noreply@blogger.comtag:blogger.com,1999:blog-2214461049219354662.post-56212013666273660842015-11-04T06:40:31.279+04:002015-11-04T06:40:31.279+04:00Assalamualaikum, I have difficulties understanding...Assalamualaikum, I have difficulties understanding solution 434, why does the pd between p and s equals to 1? Anonymousnoreply@blogger.com